1) Which of the following would you NOT see on a Windows 10 Start menu?

There will be 10 numbers stored contiguously in the computer at location x 7000 . Write a complete LC-3 program, starting at loc

Artist 52 [7]

Answer:

The LC-3 (Little Computer 3) is an ISA definition for a 16-bit computer. Its architecture includes physical memory mapped I/O via a keyboard and display; TRAPs to the operating system for handling service calls; conditional branches on N, Z, and P condition codes; a subroutine call/return mechanism; a minimal set of operation instructions (ADD, AND, and NOT); and various addressing modes for loads and stores (direct, indirect, Base+offset, PC-relative, and an immediate mode for loading effective addresses). Programs written in LC-3 assembler execute out of a 65536 word memory space. All references to memory, from loading instructions to loading and storing register values, pass through the get Mem Adr() function. The hardware/software function of Project 5 is to translate virtual addresses to physical addresses in a restricted memory space. The following is the default, pass-through, MMU code for all memory references by the LC-3 simulator.

unsigned short int get Mem Adr(int va, int rwFlg)

{

unsigned short int pa;

// Warning: Use of system calls that can cause context switches may result in address translation failure

// You should only need to use gittid() once which has already been called for you below. No other syscalls

// are necessary.

TCB* tcb = get TCB();

int task RPT = tcb [gettid()].RPT;

pa = va;

// turn off virtual addressing for system RAM

if (va < 0x3000) return &memory[va];

return &memory[pa];

} // end get MemAdr

Simple OS, Tasks, and the LC-3 Simulator

We introduce into our simple-os a new task that is an lc3 Task. An lc3 Task is a running LC-3 simulator that executes an LC-3 program loaded into the LC-3 memory. The memory for the LC-3 simulator, however, is a single global array. This single global array for memory means that alllc3 Tasks created by the shell use the same memory for their programs. As all LC-3 programs start at address 0x3000 in LC-3, each task overwrites another tasks LC-3 program when the scheduler swaps task. The LC-3 simulator (lc3 Task) invokes the SWAP command every several LC-3 instruction cycles. This swap invocation means the scheduler is going to be swapping LC-3 tasks before the tasks actually complete execution so over writing another LC-3 task's memory in the LC-3 simulator is not a good thing.

You are going to implement virtual memory for the LC-3 simulator so up to 32 LC-3 tasks can be active in the LC-3 simulator memory without corrupting each others data. To implement the virtual memory, we have routed all accesses to LC-3 memory through a get Mem Adr function that is the MMU for the LC-3 simulator. In essence, we now have a single LC-3 simulator with a single unified global memory array yet we provide multi-tasking in the simulator for up to 32 LC-3 programs running in their own private address space using virtual memory.

We are implementing a two level page table for the virtual memory in this programming task. A two level table relies on referring to two page tables both indexed by separate page numbers to complete an address translation from a virtual to a physical address. The first table is referred to as the root page table or RPT for short. The root page table is a fixed static table that always resides in memory. There is exactly one RPT per LC-3 task. Always.

The memory layout for the LC=3 simulator including the system (kernel) area that is always resident and non-paged (i.e., no virtual address translation).

The two figures try to illustrate the situation. The lower figure below demonstrates the use of the two level page table. The RPT resident in non-virtual memory is first referenced to get the address of the second level user page table or (UPT) for short. The right figure in purple and green illustrates the memory layout more precisely. Anything below the address 0x3000 is considered non-virtual. The address space is not paged. The memory in the region 0x2400 through 0x3000 is reserved for the RPTs for up to thirty-two LC-3 tasks. These tables are again always present in memory and are not paged. Accessing any RPT does not require any type of address translation.

The addresses that reside above 0x3000 require an address translation. The memory area is in the virtual address space of the program. This virtual address space means that a UPT belonging to any given task is accessed using a virtual address. You must use the RPT in the system memory to keep track of the correct physical address for the UPT location. Once you have the physical address of the UPT you can complete the address translation by finding the data frame and combining it with the page offset to arrive at your final absolute physical address.

A Two-level page table for virtual memory management.

x7000 123F x7000 0042

x7001 6534 x7001 6534

x7002 300F x7002 300F

x7003 4005 after the program is run, memory x7003 4005

x7004 3F19

7 0

2 years ago

Read 2 more answers

Methods for preventing/overcoming group conflict include all EXCEPT:

kondor19780726 [428]

Answer:

recognizing that gender differences are a myth.

Explanation:

The options are:

active listening.
recognizing that gender differences are a myth.
structured debate.
building cross-cultural understanding

Without active listening, structured debate, and cross-cultural understanding group conflict are definitely on the card. However, no one now is concerned about gender differences. As now both the genders are already having the equal status in at least developed countries. However, this too can play a role in avoiding group conflict. However, since this is not that important considering the current context, this looks like being the correct option here. Hence, the above mentioned in the answer section is the correct option.

7 0

2 years ago

c++ Write a program that reads a list of words. Then, the program outputs those words and their frequencies. The input begins wi

Margaret [11]

Answer:

The following are the program in the C++ Programming Language:

#include <iostream> //header file

#include <string> //header file

#include <vector> //header file

//name space

using namespace std;

//main function

int main() {

vector<string> word; //set variable

vector<int> c; //set variable

int s, counts = 0; //set variable

string strng; //set variable

cout<<"Enter the size of string: "; //print message

cin >> s; //get input

cout<<"Enter the string: "; //print message

for(int i = 0; i < s; ++i) { //set for loop

cin >> strng; //get input

word.push_back(strng);

}

for(int i = 0; i < s; ++i) { //set for loop

counts = 0;

for(int j = 0;j<word.size();j++){ //set for loop

if(word[j] == word[i]){ //set if statement

counts++; //increament in counts

}

c.push_back(counts);

}

for(int i = 0; i < s; ++i) {

cout << word[i] << " " << c[i] << endl;//print result

}

return 0;

}

<u>Output</u>:

Enter the size of string: 2

Enter the string: hello sir

hello 1

sir 1

Explanation:

Here, we define three header files <iostream>, <String>, <vector> and namespace "std" after that we define main() method inside it.

Then, we set two vector type variables first one is string variable "word" and the second one is integer variable "c".
Then we set two integer variable "s" and "counts" and variable "counts" assign to 0.
Then, we get input from the user in variable "s" for the length of the loop.
Then, we set for the loop inside it, we get input in the variable "strng" from the user.
Then, we set the for loop for count the string repetition if any word comes again in the string then the value of count will increase.
Finally, we set for a loop to print the result.

4 0

2 years ago

The power of if worksheet

sergejj [24]

What are you talking about?

3 0

2 years ago

LILLE VIC LUNCUL ANCI.

tatiyna

The correct option is C. toward the floor.

The magnetic force on the moving negative charge acts towards the floor.

<u>Explanation</u>:

The direction of the force applied on the moving charged particle placed in the magnetic field can be determined with the help of Fleming’s Left hand rule.

The current flows in the direction opposite to the direction of electron. If the electron moves from negative terminal to positive terminal, then the current will flow from positive terminal to negative terminal.

As given, the direction of electron- South to North

So the direction of current will be- North to South

Using Fleming's Left hand rule we get the direction of force in downward direction, i.e. towards the floor.

5 0

3 years ago