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<span>When (1, 2) is substituted into the first equation, the equation is false.
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The ordered pair (1, 2) is not a solution to the system of linear equations.
The ordered pair (1, 2) is a solution to the system of linear equations.</span>
<span> i'm going to be slightly extra careful in showing each step. specific, ln [n / (n+a million) ]= ln n - ln(n+a million). So, we've sum(n=a million to infinity) ln [n / (n+a million) ] = lim(ok--> infinity) sum(n=a million to ok) ln [n / (n+a million) ] = lim(ok--> infinity) sum(n=a million to ok) [ln n - ln(n+a million)] = lim(ok--> infinity) (ln a million - ln 2) + (ln 2 - ln 3) + ... + (ln ok - ln(ok+a million)) = lim(ok--> infinity) (ln a million - ln(ok+a million)), for the reason that fairly much all the words cancel one yet another. Now, ln a million = 0 and lim(ok--> infinity) ln(ok+a million) is countless. So, the sum diverges to -infinity. IM NOT COMPLETELY SURE
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I hope this is the answer you want
Answer:
74940, three
Step-by-step explanation:
74.94 × 10³
74.94 × 1000
74940
2r+7+2n+n2
Because I combined the ones with like terms.