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stealth61 [152]
3 years ago
14

What is 60% of 125?

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
5 0

60% of 125

.60 * 125

75

Step2247 [10]3 years ago
5 0

Answer:

try turning 60% into a fraction

Step-by-step explanation:

60/100 * 125/1=7500/100 reduced is 75/100 75%

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Heidi swims 2/3 of a kilometer in 2/3 of an hour.What is Heidi’s speed in kilometers per hour? Show your work or explain how you
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3 years ago
how do you rewrite : y=x^2-5x+9 in standard form using complying the square? I keep getting to : x^2-5x-25/4 but I’m not allowed
yawa3891 [41]

I presume with this you meant to say you want this equation in <u>general form</u>, also known as vertex form, which is y = a(x - h)² + k, instead of <u>standard form</u>, which is y = ax² + bx + c, which is what the original equation is already in.

So with completing the square, you first have to isolate the x-terms. To do this, subtract 9 on both sides of the equation:

y-9=x^2-5x

Next, we want to make the right side of the equation a perfect square. To find the constant of this soon-to-be perfect square, divide the x-coefficient by 2 and square that quotient. In this case:

-5\div 2 = -\frac{5}{2}\\\\(-\frac{5}{2})^2=-\frac{5}{2}\times-\frac{5}{2}=\frac{25}{4}

Now add 25/4 on both sides of the equation:

y-9+\frac{25}{4}=x^2-5x+\frac{25}{4}

Now to combine -9/1 and 25/4, they must have the same denominator, and to find it you must find the LCD, or lowest common denominator, of 1 and 4. To find it, list the multiples of both and the lowest one they share is their LCD. In this case, the LCD is 4. Multiply both sides of -9/1 by 4/4 and then add the numerators up:

-\frac{9}{1}\times \frac{4}{4}=-\frac{36}{4}\\\\-\frac{36}{4}+\frac{25}{4}=-\frac{11}{4}\\\\y-\frac{11}{4}=x^2-5x+\frac{25}{4}

Next, we need to factor the right side of the equation. Using this format of a^2-2ab+b^2=(a-b)^2 , we can factor it as:

y-\frac{11}{4}=(x-\frac{5}{2})^2

Now lastly, add both sides by 11/4, and <u>your final answer will be y=(x-\frac{5}{2})^2+\frac{11}{4}</u>

8 0
4 years ago
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