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VikaD [51]
2 years ago
13

How do I find the all of the angle measures of a kite with only one given angle?

Mathematics
1 answer:
ohaa [14]2 years ago
8 0
Use the geometery rules of a kite to fiugure it out
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HELP I WILL MARK YOU AS A BRAINLIEST!!!
DaniilM [7]

Answer:

The answer is D $15.50

Hopes it Helps!

3 0
2 years ago
The relationship between the number of years (x) that have passed and the population (y) for a small town is shown in the table.
ZanzabumX [31]

Answer:

D. 10,699

Step-by-step explanation:

The given data for the Population Count Per Year is presented as follows;

Number of Years (x); 1, 2, 3, 4, 5, 6, 7, 8

\begin{array}{ccccccccc}Number \ of \ Years \ (x)&1&2&3&4&5&6&7&8\\Population \ (y)&1,440&1,728&2,074&2,488&2,986&3,583&4,300&5,160\end{array}The data regression equation is y = 1,200·(1.2)ˣ

Based on the regression equation for the data, the predicted value of the town's population after 12 years is given by substituting x = 12 as follows;

After 12 years, y = 1,200 × (1.2)¹² ≈ 10,699.32

Therefore, the option which is the best prediction is 10,699.

7 0
3 years ago
A gopher lives in an underground burrow. It starts at a certain point, p, underground and digs straight down to triple its dista
saw5 [17]

Answer:

<-2

Step-by-step explanation:

4 0
2 years ago
On a number line what is the distance between -12 and 20 ??
KIM [24]

Answer:  Step-by-step explanation:

In order to answer this question you will need to find 2 distances and then add them to each other.

Begin at -29.  How far will you have to move to the right 29 in order to get to 0?

Now how far will you have to more to get from 0 to 100?

Draw an open number line to help you.

_____________________________________________________

-29                                           0                                                   100

Your first distance is 29.  Your second distance is 100.  The total distance is 129.

3 0
3 years ago
Can someone solve this for me?
Helga [31]

well, we know it's a rectangle, so that means the sides JK = IL and JI = KL, so

\stackrel{JK}{3x+21}~~ = ~~\stackrel{IL}{6y}\implies 3(x+7)=6y\implies x+7=\cfrac{6y}{3} \\\\\\ x+7=2y\implies \boxed{x=2y-7} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{JI}{6y-6}~~ = ~~\stackrel{KL}{2x+20}\implies 6(y-1)=2(x+10)\implies \cfrac{6(y-1)}{2}=x+10 \\\\\\ 3(y-1)=x+10\implies 3y-3=x+10\implies \stackrel{\textit{substituting from the 1st equation}}{3y-3=(2y-7)+10} \\\\\\ 3y-3=2y+3\implies y-3=3\implies \blacksquare~~ y=6 ~~\blacksquare ~\hfill \blacksquare~~ \stackrel{2(6)~~ - ~~7}{x=5} ~~\blacksquare

5 0
1 year ago
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