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Vlada [557]
2 years ago
11

x = 10 - 6" alt="x + 6 = 10 \\ x = 10 - 6" align="absmiddle" class="latex-formula">
simultaneous equations
​
Mathematics
1 answer:
tia_tia [17]2 years ago
6 0

Answer:

False.

These are not simultaneous equations.

Step-by-step explanation:

Simultaneous equations are equations involving two or more unknowns that are to have the same values in each equation. In the equations given there is only one unknown value.

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A right angles has 2 sides 157 and 168 what is the other length
just olya [345]

Step-by-step explanation:

we can find the length of other side by hypotenuse formula,

which is h² = a² + b²

so,

a = 157

b = 168

now after inserting the values we got,

→ h² = (157)² + (168)²

→ h = 24649 + 28224

→ h = 52,873

→ h² = √52873 = 229.94

so, length of other side is 229.94

<em>hope </em><em>this</em><em> answer</em><em> helps</em><em> you</em><em> dear</em><em>!</em><em> </em><em>take </em><em>care</em><em> </em><em>and </em><em>may</em><em> u</em><em> have</em><em> a</em><em> great</em><em> day</em><em> </em><em>ahead!</em>

3 0
3 years ago
HELP ASPAP!! ANSWER CORRECLTY
d1i1m1o1n [39]

Answer:

17

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Tìm căn bậc hai của số phức z=1+i√3
Anni [7]

Write <em>z</em> in polar form:

<em>z</em> = 1 + √3 <em>i</em> = 2 exp(<em>i</em> <em>π</em>/3)

Taking the square root gives two possible complex numbers,

√<em>z</em> = √2 exp(<em>i</em> (<em>π</em>/3 + 2<em>kπ</em>)/2)

with <em>k</em> = 0 and <em>k</em> = 1, so that

√<em>z</em> = √2 exp(<em>i</em> <em>π</em>/6) = √(3/2) + √(1/2) <em>i</em>

and

√<em>z</em> = √2 exp(<em>i</em> 7<em>π</em>/6) = -√(3/2) - √(1/2) <em>i</em>

5 0
3 years ago
Convert the following equation to slope-intercept form to graph: 7x -y = -3
Illusion [34]

Answer:

7x-y=-3

-y=-7x-3

divide by -1 through out

therefore : y=7x+3<em />

7 0
3 years ago
A series contains 18 numbers and has a sum of 4,185. The last number of the series is 275. What is the first number?
N76 [4]
If the series is made up of numbers in an arithmetic progression, you have

\displaystyle\sum_{n=1}^{18}a_n=\sum_{n=1}^{18}(a_1+(n-1)d)=18a_1+153d=4185

where a_1 is the first term and d is the common difference between terms.

Since the last term in the series is a_{18}=275, you have

a_{18}=a_1+(18-1)d\implies a_1+17d=275

Solve the system

\begin{cases}18a_1+153d=4185\\a_1+17d=275\end{cases}

and you'll find that the first term is a_1=190 (with d=5).
5 0
4 years ago
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