Question

A concession stand sells hamburgers (h) for $2 and hotdogs(d) for $1.On friday night they sold a total of 300 hamburgers and hotdogs and made $420.How many of each did they sell?
Which system of equations matches the situation?
A)h+d=300
2h+d=420

B)h+d=420
2h+d=300

C)h+d=300
h+2d=420

D) h+d=720
2h+d=300

Answer 1

The first equation has to be the sum of hotdogs and hamburgers. Since a total of 300 hamburgers and hotdogs was sold, the first equation is:
          h+d=300

Now, the second equation is about the money. They say that EACH hamburger cost $2 and each hotdog cost $1. And, the total amount of money made was $420. So the second equation is:

      2h+d=420

SO, overall, the system of equations is this:

   h+d=300
   2h+d=420
     
(option A is the answer)