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2 years ago

Find the product of (3^6)(3)(3^5) Express your answer using exponents

Mathematics

2 answers:

VikaD [51]2 years ago

6 0

Answer:

3^12

Step-by-step explanation:

When multiplying the same number with different exponents you have to add the the exponents. For example:

$a^x + a^y = a ^{x+y}$

So (3^6)(3)(3^5) or (3^6)(3^1)(3^5) = 3^(6+1+5) = 3^12

andreev551 [17]2 years ago

4 0

Answer:

3^12

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago

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Marissa bought four bottles of water Each bottle of water is 0.95 cents Write an equation with the same product as the total cos

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Answer: Total cost = Cost of each bottle × Number of bottles

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2 years ago

Simplify Negative 15.6 divided by negative 4.

masha68 [24]

Simplify:

-15.6/-4

( $\frac{-15.6}{-4}$ )

Divide to solve:

You get 3.9

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2 years ago

If the angles of a quadrilateral are 140, 80, 60, 80 then what type of quadrilateral could it be?

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Consider the following. f(x) = x5 − x3 + 6, −1 ≤ x ≤ 1 (a) Use a graph to find the absolute maximum and minimum values of the fu

kykrilka [37]

ANSWER

See below

EXPLANATION

Part a)

The given function is

$f(x) = {x}^{5} - {x}^{3} + 6$

From the graph, we can observe that, the absolute maximum occurs at (-0.7746,6.1859) and the absolute minimum occurs at (0.7746,5.8141).

b) Using calculus, we find the first derivative of the given function.

$f'(x) = 5 {x}^{4} - 3 {x}^{2}$

At turning point f'(x)=0.

$5 {x}^{4} - 3 {x}^{2} = 0$

This implies that,

${x}^{2} (5 {x}^{2} - 3) = 0$

${x}^{2} = 0 \: or \: 5 {x}^{2} - 3 = 0$

$x = - \frac{ \sqrt{15} }{5} \: or \: x = 0 \: \: or \: x =\frac{ \sqrt{15} }{5}$

We plug this values into the original function to obtain the y-values of the turning points

$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} +750)) \:and \: (0, - 6) \: and\: ( \frac{ \sqrt{15} }{5} , \frac{1}{125} ( - 6 \sqrt{15} +750))$