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2 years ago

What IS the slope of a line that is perpendicular to the line y= --x + 5?

Mathematics

1 answer:

Black_prince [1.1K]2 years ago

3 0

<h3>Slopes of perpendicular lines.</h3>

Let k: y = a₁x + b₁ and l: y = a₂x + b₂. Then

We have the line y = -x + 5 ⇒ a₁ = -1.

Therefore

a₂ · (-1) = -1

-a₂ = -1 I<em>change the signs</em>

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3 years ago

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3 years ago

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Given P(A)=0.78P(A)=0.78, P(B)=0.65P(B)=0.65 and P(A\cup B)=0.873P(A∪B)=0.873, find the value of P(A\cap B)P(A∩B), rounding to t

Sever21 [200]

Answer:

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Step-by-step explanation:

Given

$P(A) = 0.78$

$P(B) = 0.65$

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Required

Determine $P(A\ n\ B)$

From laws of probability, we have:

$P(A\ n\ B) = P(A) + P(B) - P(A\ u\ B)$

Substitute in values

$P(A\ n\ B) = 0.78 + 0.65 - 0.873$

$P(A\ n\ B) = 0.557$

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rodikova [14]

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Step-by-step explanation:

a) Data and Calculations:

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