What is 32% as a fraction in simplest form? A) 0.32 100 B) 1.6 12 C) 8 25 D) 1 16

Find the area of the irregular figure. plssss

Flauer [41]

Answer:

366cm²

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The first term in the sequence below is 2.

Art [367]

-7n + 9 because the common difference is -7, so you have -7n, and then by plugging in the term numbers and the values, you find out that you need to add 9 to the -7n, so the answer is -7n + 9

3 0

3 years ago

How much greater is the area of a square with a side length of 9 inches than the area of a circle with a radius of 3 inches?

fredd [130]

The area of the square is 81 sq in, and the area of the circule is (3.14)(3 in)^2, or approx 3.14(9) sq in, or approx 28.27 sq in.

Subtract: 81 sq in - 28.27 sq in = approx. 52.73 sq in.

The difference is 52.73 sq in; the square is larger, the circle smaller.

7 0

3 years ago

Which expression is equivalent to square root 55x^7 y^6/11x^11 y^8? Assume x > 0 and y > 0.

morpeh [17]

The first step for solving this expression is to reduce the fraction with 11.
$\sqrt{ \frac{5 x^{7} y^{6} }{ x^{11} y^{8} } }$
Now reduce the fraction with $x^{7}$ .
$\sqrt{ \frac{5 y^{6} }{ x^{4} y^{8} } }$
Reduce the fraction one more time with $y^{6}$ .
$\sqrt{ \frac{5}{ x^{4} y^{2} } }$
To take the root of a fraction,, we must take the root of the numerator and denominator separately. This rule will change the expression to the following:
$\frac{ \sqrt{5} }{ x^{2} y}$
Since we cannot simplify this fraction any further,, the final answer is going to be $\frac{ \sqrt{5} }{ x^{2} y}$ .
Let me know if you have any further questions.
:)

3 0

3 years ago

Read 2 more answers

The Consumer Price Index (CPI) is a measure of the change in the cost of goods over time. If 1982 is used as the base year of c

Mashcka [7]

Answer:

a) $y = 3.8 x +100$

b) $Abs. change= |168.4-167.5|=0.9$

So the calculated value is 0.9 points above the actual value.

$Relative. Change =\frac{|168.4 -167.5|}{167.5}x100 =0.537$ %

And the calculated value it's 0.537% higher than the actual value.

c) For this case we can use the slope obtained from the linear model to answer this question, and we can conclude that the CPI is increasing at approximate 3.8 units per year.

Step-by-step explanation:

Data given

1982 , CPI=100

1986, CPI = 191.2

Notation

Let CPI the dependent variable y. And the time th independent variable x.

For this case we want to adjust a linear model givn by the following expression:

$y=mx+b$

Solution to the problem

Part a

For this case we can find the slope with the following formula:

$m =\frac{CPI_{2006}-CPI_{1982}}{2006-1982}$

And if we replace we got:

$m =\frac{191.2-100}{2006-1982}=3.8$

Let X represent the number of years after. Then for 1982 t = 0, and if we replace we can find b:

$100 = 3.8(0)+b$

And then $b=100$

So then our linear model is given by:

$y = 3.8 x +100$

Part b

For this case we need to find the years since 1982 and we got x = 2000-1982=18, and if we rpelace this into our linear model we got:

$y = 3.8(18) +100=168.4$

And the actual value is 167.5 we can compare the result using absolute change or relative change like this:

$Abs. change= |168.4-167.5|=0.9$

So the calculated value is 0.9 points above the actual value.

And we can find also the relative change like this:

$Relative. Change =\frac{|Calculated -Real|}{Real}x100$

And if we replace we got:

$Relative. Change =\frac{|168.4 -167.5|}{167.5}x100 =0.537$ %

And the calculated value it's 0.537% higher than the actual value.

Part c

For this case we can use the slope obtained from the linear model to answer this question, and we can conclude that the CPI is increasing at approximate 3.8 units per year.

3 0

3 years ago