Calculate: 1/1x3+1/3x5+…+1/47x49

Mathematics

1 answer:

shtirl [24]2 years ago

3 0

Answer:

24/49

Step-by-step explanation:

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I need help can someone explain this simply

statuscvo [17]

In order to do this, you have to use the Pythagorean Theorem which is a^2 +b^2=c^2 It does not matter in what order a and b are, but c is always the hypotenuse or the side across from the right angle. First, you substitute 24 in for a and 45 in for b so your equation so far would look like 24^2 + 45^2 = c^2 Then, you square 24 and 45 and get 576+2025=c^2 Then you add the two to get 2601=c^2 Finally, you would square root both sides and get 51=c So the width of the recycling bin is 51 inches long

8 0

3 years ago

How many digits are in the repetend of the decimal expansion for 2/41

AleksandrR [38]

Answer:

0.0487804878

Step-by-step explanation:

the answer will be 5 because it starts at 0.

5 0

3 years ago

I am offering another 100 points

Ivahew [28]

Answer:

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

Step-by-step explanation:

Perfect squares: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...

To find $\sf \sqrt{75}$ , identify the perfect squares immediately before and after 75:

64 and 81

$\begin{aligned}\sf As\;\; 64 < 75 < 81\; & \implies \sf \sqrt{64} < \sqrt{75} < \sqrt{81}\\&\implies \sf \;\;\;\;\;8 < \sqrt{75} < 9 \end{aligned}$

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

See the attachment for the correct placement of $\sf \sqrt{75}$ on the number line.