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Artyom0805 [142]
2 years ago
8

For the upcoming parade, Lauren needed to make her school's triangular flag into a larger, similar triangular flag. Using the in

formation given, determine which (if any) similarity postulate she used in making her school's new flag.

Mathematics
1 answer:
aliina [53]2 years ago
4 0

In order to make the new flag, Lauren decided to triple the sides of the old flag in order to get a new one.

<h3>What is the difference between these triangles</h3>

The old triangle is the smaller one. We can see that this triangle has increased by a factor of 3 on all sides.

We have 4 x 3= 12

2 x 3 = 6

7 x 3 = 21

The calculated values above is what produced the new larger flag.

Read more on triangles here:

brainly.com/question/17335144

#SPJ1

You might be interested in
on Saturday quentin will earn 15.00 more than 2 times the amount of money he earned on Friday. if quentin earned d dollars on Fr
Basile [38]

$15 more, than twice Friday's earnings

d is how much he earned on Friday

s is how much he earned on Saturday

2d + 15 = s

6 0
3 years ago
HELPPPP<br> Which of the following is a solution of x2 + 5x = -2? (2 points)
harkovskaia [24]

Answer:

5.372 or −0.372

Step-by-step explanation:Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".

Step by step solution :

STEP

1

:

Trying to factor by splitting the middle term

1.1     Factoring  x2-5x-2

The first term is,  x2  its coefficient is  1 .

The middle term is,  -5x  its coefficient is  -5 .

The last term, "the constant", is  -2

Step-1 : Multiply the coefficient of the first term by the constant   1 • -2 = -2

Step-2 : Find two factors of  -2  whose sum equals the coefficient of the middle term, which is   -5 .

     -2    +    1    =    -1

     -1    +    2    =    1

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

1

:

 x2 - 5x - 2  = 0

STEP

2

:

Parabola, Finding the Vertex

2.1      Find the Vertex of   y = x2-5x-2

Parabolas have a highest or a lowest point called the Vertex .   Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) .   We know this even before plotting  "y"  because the coefficient of the first term, 1 , is positive (greater than zero).

Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two  x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.

Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.

For any parabola,Ax2+Bx+C,the  x -coordinate of the vertex is given by  -B/(2A) . In our case the  x  coordinate is   2.5000  

Plugging into the parabola formula   2.5000  for  x  we can calculate the  y -coordinate :

 y = 1.0 * 2.50 * 2.50 - 5.0 * 2.50 - 2.0

or   y = -8.250

Parabola, Graphing Vertex and X-Intercepts :

Root plot for :  y = x2-5x-2

Axis of Symmetry (dashed)  {x}={ 2.50}

Vertex at  {x,y} = { 2.50,-8.25}

x -Intercepts (Roots) :

Root 1 at  {x,y} = {-0.37, 0.00}

Root 2 at  {x,y} = { 5.37, 0.00}

Solve Quadratic Equation by Completing The Square

2.2     Solving   x2-5x-2 = 0 by Completing The Square .

Add  2  to both side of the equation :

  x2-5x = 2

Now the clever bit: Take the coefficient of  x , which is  5 , divide by two, giving  5/2 , and finally square it giving  25/4

Add  25/4  to both sides of the equation :

 On the right hand side we have :

  2  +  25/4    or,  (2/1)+(25/4)

 The common denominator of the two fractions is  4   Adding  (8/4)+(25/4)  gives  33/4

 So adding to both sides we finally get :

  x2-5x+(25/4) = 33/4

Adding  25/4  has completed the left hand side into a perfect square :

  x2-5x+(25/4)  =

  (x-(5/2)) • (x-(5/2))  =

 (x-(5/2))2

Things which are equal to the same thing are also equal to one another. Since

  x2-5x+(25/4) = 33/4 and

  x2-5x+(25/4) = (x-(5/2))2

then, according to the law of transitivity,

  (x-(5/2))2 = 33/4

We'll refer to this Equation as  Eq. #2.2.1  

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

  (x-(5/2))2   is

  (x-(5/2))2/2 =

 (x-(5/2))1 =

  x-(5/2)

Now, applying the Square Root Principle to  Eq. #2.2.1  we get:

  x-(5/2) = √ 33/4

Add  5/2  to both sides to obtain:

  x = 5/2 + √ 33/4

Since a square root has two values, one positive and the other negative

  x2 - 5x - 2 = 0

  has two solutions:

 x = 5/2 + √ 33/4

  or

 x = 5/2 - √ 33/4

Note that  √ 33/4 can be written as

 √ 33  / √ 4   which is √ 33  / 2

Solve Quadratic Equation using the Quadratic Formula

2.3     Solving    x2-5x-2 = 0 by the Quadratic Formula .

According to the Quadratic Formula,  x  , the solution for   Ax2+Bx+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

                                   

           - B  ±  √ B2-4AC

 x =   ————————

                     2A

 In our case,  A   =     1

                     B   =    -5

                     C   =   -2

Accordingly,  B2  -  4AC   =

                    25 - (-8) =

                    33

Applying the quadratic formula :

              5 ± √ 33

  x  =    —————

                   2

 √ 33   , rounded to 4 decimal digits, is   5.7446

So now we are looking at:

          x  =  ( 5 ±  5.745 ) / 2

Two real solutions:

x =(5+√33)/2= 5.372

or:

x =(5-√33)/2=-0.372

6 0
3 years ago
Write an equation in intercept form of the parabola that passes through the point (3,40) and has x-intercepts −5 and 4.
Maru [420]
The equation of this parabola will have the form f(x) = a(x+5)(x-4), which works out to f(x) = a(x^2 + x - 20).  Since the parabola passes thru (3,40),

40 = a(3^2 + 3 - 20), or 40 = a(-8), so a = -5.

Thus, the equation of this parabola is     y = -5(x^2 + x - 20).
5 0
3 years ago
If you are dealt five cards from a shuffled deck of 52 cards find the probability of getting three queens and two kings
dexar [7]

The probability of getting three queens and two kings is \frac{1}{1082900}

<u>Solution:</u>

Given that , you are dealt five cards from a shuffled deck of 52 cards  

We have to find the probability of getting three queens and two kings  

Now, we know that, in a deck of 52 cards, we will have 4 queens and 4 kings.

\text { probability of an event }=\frac{\text { favarable possibilities }}{\text { number of possibilities }}

<em><u>Probability of first queen:</u></em>

\text { Probability for } 1^{\text {st }} \text { queen }=\frac{4}{52}=\frac{1}{13}

<em><u>Probability of second queen:</u></em>

\text { Plobability for } 2^{\text {nd }} \text { queen }=\frac{3}{51}=\frac{1}{17}

Here we used 3 for favourable outcome, since we already drew 1 queen out of 4

And now number of outcomes = 52 – 1 = 51

<em><u>Probability of third queen:</u></em>

Similarly here favorable outcome = 2, since we already drew 2 queen out of 4

And now number of outcomes = 51 – 1 = 50

\text { Probability of } 3^{\text {rd }} \text { queen }=\frac{2}{50}=\frac{1}{25}

<em><u>Probability for first king:</u></em>

Here kings are 4, but overall cards are 49 as 3 queens are drawn

\text { probability for } 1^{\text {st }} \text { king }=\frac{4}{49}

<em><u>Probability for second king:</u></em>

Here, kings are 3 and overall cards are 48 as 3 queens and 1 king are drawn

\text { probability of } 2^{\text {nd }} \text { king }=\frac{3}{48}=\frac{1}{16}

<em><u>And, finally the overall probability to get 3 queens and 2 kings is:</u></em>

=\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} \times \frac{4}{49} \times \frac{1}{16}=\frac{4}{4331600}=\frac{1}{1082900}

Hence, the probability is \frac{1}{1082900}

7 0
3 years ago
Please help, I need an explanation on how to do this type of problems. I've been at this assignment for the whole day and I'm ne
laila [671]

Answer:

See image

Step-by-step explanation:

To graph the inequality

-2x + y >= -10

Change it to y = mx + b form, use a solid line (bc of the "or equal to" underline)

y >= 2x - 10 We have y-intercept at -10 and slope 2/1, shading goes above the line.

The other graph is an absolute value graph; it has a v-shape. The 7 makes it stretched 7 times taller (and skinnier) the -4 by the x shifts the whole graph to the right 4 units. The -4 at the end of the equation shifts the whole graph down 4 units. See image. The shading goes above the V (kind of looks like inside)

The solution to the system is where the shading of the two overlap. It is mostly the shading for the absolute value graph except for a tiny triangle at the bottom. See image.

4 0
2 years ago
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