The length of a rectangle is six times it’s width. If the area of the rectangle is 600 ft squared find the perimeter

you can buy 5 cans of green beans at the village market for $3 you can buy 10 of the same cans of beans at Sams Club for $6.10 w

ioda

Each can of green beans costs ($3.00/5) = 60¢ at the
village market, and ($6.10/10) = 61¢ at Sam's Club.

If you're watching every penny, then that MIGHT be enough
of a difference to make you decide to buy your beans at the
village market, but not necessarily.

If, say, the village market is farther away from you, or if there are
other things you're going to get from Sam's anyway, then you
should buy your beans there too.

6 0

3 years ago

23. A certain type of gasoline is supposed to have a mean octane rating of at least 90. Suppose measurements are taken on of 5 r

Nostrana [21]

Answer:

a) $p_v =P(Z$

b) Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

c) $P(\bar X >90)=1-P(Z$

$1-P(Z$

d) For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We can calculate the sample mean and deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

$\bar X=88.96$ represent the sample mean

$s=1.011$ represent the sample standard deviation

n=5 represent the sample selected

$\alpha$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 90, the system of hypothesis would be:

Null hypothesis: $\mu \geq 90$

Alternative hypothesis: $\mu < 90$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{88.96-90}{\frac{0.8}{\sqrt{5}}}=-2.907$

Part a

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=5-1 = 4$

Then since is a left tailed test the p value would be:

$p_v =P(Z$

Part b

Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

Part c

We want this probability:

$P(\bar X$

The best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we apply this formula to our probability we got this:

$P(\bar X >90)=1-P(Z$

$1-P(Z$

Part d

For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

7 0

3 years ago

mortar is made by mixing water cement and sand in the following ratio 1 : 2 : 3 . how much of each component is needed to make 3

nikitadnepr [17]

Answer:

To make 3 kg of water, we need

0.5 kg water

1 kg cement

1.5kg sand

Step-by-step explanation:

Here, we want to calculate the mass of each component needed to make 3 kg of mortar

We work with the ratio

Total ratio is:

1 + 2 + 3 = 6

water

1/6 * 3kg = 0.5 kg

cement

2/6 * 3 kg = 1 kg

sand

3/6 * 3 = 1.5 kg

3 0

3 years ago

Which values are outliers?

kirill115 [55]

How to compute outliers:

1) Data in chronological order:
0.8 ; 1.6 ; 3.9 ; 3.9 ; 4.4 ; 4.5 ; 6.1 ; 6.4 ; 6.5 ; 10.6 ; 11.2

2) Get median: There are 11 numbers, the 6th number is the median.
median: 4.5

3) Get Q1 and Q3.
Q1: 3.9 ; Q3 = 6.45

4) Find IQR. IQR = Q3 - Q1
IQR = 6.45 - 3.9
IQR = 2.55

5) Find inner fence and outer fence:
Multiply IQR by 1.5 → 2.55 x 1.5 = 3.825
Add result to Q3: 6.45 + 3.825 = 10.275 outer fence
Deduct result from Q1: 3.9 - 3.825 = 0.075 inner fence

Outlier are outside the 0.075 - 10.275 range

<span>Data Outlier Not Outlier
0.8 x
1.6 x
10.6 x
11.2 x</span>

6 0

4 years ago

Read 2 more answers

How many solutions would y=-4x+11 and -6x+y=11 have?

likoan [24]

Answer:

1 solution

Step-by-step explanation:

There is only one solution as it is not a quadratic

4 0

3 years ago