Answer:
5
Step-by-step explanation:
u gotta add the H's with The U's and then ye
Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Answer:
50
Step-by-step explanation:
trust me bro
Answer:
-8n + 9
Step-by-step explanation:
Given that,
A = -3n + 2
B = 5n - 7
Before solving you have to know that,
( + ) × ( + ) = ( + )
( - ) × ( - ) = ( + )
( + ) × ( - ) = ( - )
Let us solve now.
A - B
-3n + 2 -(5n - 7)
-3n + 2 - 5n + 7
Combine like terms
-3n - 5n + 2 + 7
-8n + 9
Hope this helps you.
Let me know if you have any other questions :-)
First, you need to set the equation equal to zero:
n^2 + 7n + 10 = 0
Now we factor. We need to find two numbers that add up to 7 and multiply to 10.
2 + 5 = 7
2 * 5 = 10
Now, we just need to write this as a polynomial:
(n + 2) (n + 5)
is our answer.
Hope this helps!
