Answer:
The probability that an 18-year-old man selected at random is greater than 65 inches tall is 0.8413.
Step-by-step explanation:
We are given that the heights of 18-year-old men are approximately normally distributed with mean 68 inches and a standard deviation of 3 inches.
Let X = <u><em>heights of 18-year-old men.</em></u>
So, X ~ Normal(
)
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
where,
= mean height = 68 inches
= standard deviation = 3 inches
Now, the probability that an 18-year-old man selected at random is greater than 65 inches tall is given by = P(X > 65 inches)
P(X > 65 inches) = P(
>
) = P(Z > -1) = P(Z < 1)
= <u>0.8413</u>
The above probability is calculated by looking at the value of x = 1 in the z table which has an area of 0.8413.
Answer with Step-by-step explanation:
We are given that A, B and C are subsets of universal set U.
We have to prove that

Proof:
Let x
Then
and 
When
then
but 
Therefore,
but 
Hence, it is true.
Conversely , Let
but 
Then
and
When
then 
Therefor,
Hence, the statement is true.
Answer:
2x -3y =1 and 3x-2y= 4 has
Step-by-step explanation:
The pair of linear equations 2x-3y=1 and 3x-2y=4 has one unique solution. , then it has a unique solution other wise not. Since , , it means the pair of linear equations has only one unique solution. Hence, the pair of linear equations 2x-3y=1 and 3x-2y=4 has only one unique solution.
a1/a2= 2/3
b1/b2= 3/-2 (-) cancle so it remains
c1 / c2 = 1/4
a1/a2 = b1/b2 not equal to c1/c2 as no solution
Answer:
The horizontal asymptote is y=0