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denpristay [2]
2 years ago
15

If

Mathematics
1 answer:
UkoKoshka [18]2 years ago
5 0

Answer:

-8n + 9

Step-by-step explanation:

Given that,

A = -3n + 2

B = 5n - 7

Before solving you have to know that,

( + ) × ( + ) = ( + )

( - ) × ( - ) = ( + )

( + ) × ( - ) = ( - )

Let us solve now.

A - B

-3n + 2 -(5n - 7)

-3n + 2 - 5n + 7

Combine like terms

-3n - 5n + 2 + 7

-8n + 9

Hope this helps you.

Let me know if you have any other questions :-)

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The heights of 18-year-old men are approximately normally distributed with mean 68 inches and standard deviation 3 inches. What
Nutka1998 [239]

Answer:

The probability that an 18-year-old man selected at random is greater than 65 inches tall is 0.8413.

Step-by-step explanation:

We are given that the heights of 18-year-old men are approximately normally distributed with mean 68 inches and a standard deviation of 3 inches.

Let X = <u><em>heights of 18-year-old men.</em></u>

So, X ~ Normal(\mu=68,\sigma^{2} =3^{2})

The z-score probability distribution for the normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = mean height = 68 inches

           \sigma = standard deviation = 3 inches

Now, the probability that an 18-year-old man selected at random is greater than 65 inches tall is given by = P(X > 65 inches)

       P(X > 65 inches) = P( \frac{X-\mu}{\sigma} > \frac{65-68}{3} ) = P(Z > -1) = P(Z < 1)

                                                                = <u>0.8413</u>

The above probability is calculated by looking at the value of x = 1 in the z table which has an area of 0.8413.

6 0
3 years ago
Prove each statement that is true and find a counterexample for each statement that is false. Assume all sets are subsets of a un
tekilochka [14]

Answer with Step-by-step explanation:

We are given that A, B and C are subsets of universal set U.

We have to prove that

A\cap (B-C)=(A\cap B)-(A\cap C)

Proof:

Let x\in A\cap (B-C)

Then x\in A and x\in(B-C)

When x\in ( B-C)then x\in B but x\notin C

Therefore, x\in( A\cap B) but x\notin (A\cap C)

Hence, it is true.

Conversely , Let x\in(A\cap B) but x\notin(A\cap C)

Then x\in A and x\in B

When x\notin ( A\cap C) then x\notin C

Therefor,x\in A\cap (B-C)

Hence, the statement is true.

5 0
3 years ago
Match each verbal description to its corresponding expression.
Aliun [14]
I need points thank you
7 0
3 years ago
The pair of linear equations 2x-3y = 14 and 3x - 2y = 4 has solution(s).<br><br>answer plz....​
Lesechka [4]

Answer:

2x -3y =1 and 3x-2y= 4 has

Step-by-step explanation:

The pair of linear equations 2x-3y=1 and 3x-2y=4 has one unique solution. , then it has a unique solution other wise not. Since , , it means the pair of linear equations has only one unique solution. Hence, the pair of linear equations 2x-3y=1 and 3x-2y=4 has only one unique solution.

a1/a2= 2/3

b1/b2= 3/-2 (-) cancle so it remains

c1 / c2 = 1/4

a1/a2 = b1/b2 not equal to c1/c2 as no solution

8 0
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What is the horizontal asymptote of the graph of f(x) = 4×5^x
Iteru [2.4K]

Answer:

The horizontal asymptote is y=0

5 0
3 years ago
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