# 2 is true
# 5 is 0.375
#8 is 8 solutions
#9 is %25
#10 is %37.5
hope this helps
for number 2: 4 times 4 equals 16 is that's why its the square root of 16.
for number 8: with red there are 3 options plus the red option so that's 4 plus the same thing with blue so that's 8.
for number 9: there is a 2/8 chance of getting that. 2/8= 25%
for number 10: there is a 3/8 chance of landing on it. 3/8= 37.5%
1. -4+5x^3-(-3y)^0
-1+-3=-4
3x^2+ 2x^1= 5x^3
9y^1-6y^1=14y^0
2. 2y-(-3x^5)+10
5y-3y=2y
-3x^1+-2x^2=-5x^3
-5x^3+2x^2=-3x^5
3. 3x+3y+8
4x^2+2x=6x^3
6x^3-3x^2=3x
7y-2y=4y
4y-y=3y
-5+(-3)=8
4. 6x^3+4y+2
3x^2+3x^1=6x^3
7y-2y=5y
5y-y=4y
I hope this helped
Answer:
Step-by-step explanation:


In exponent multiplication, if two numbers have same base, just add the exponents
In exponent division, if two numbers have same base, just subtract the exponents
Prime factorize 4 = 2*2 = 2²
4⁻¹ *(2³÷ 4⁻² )= (2²)⁻¹ * ( 2³÷ (2²)⁻²
= (2⁻²)* (2³ ÷2⁻⁴)
![= 2^{-2} * (2^{3-[-4]})\\\\= 2^{-2} * (2^{3+4})\\\\= 2^{-2} * 2^{7}\\\\= 2^{-2+7}\\\\= 2^{5}\\\\= 2 * 2 * 2 * 2 * 2\\\\= 32](https://tex.z-dn.net/?f=%3D%202%5E%7B-2%7D%20%2A%20%282%5E%7B3-%5B-4%5D%7D%29%5C%5C%5C%5C%3D%202%5E%7B-2%7D%20%2A%20%282%5E%7B3%2B4%7D%29%5C%5C%5C%5C%3D%202%5E%7B-2%7D%20%2A%202%5E%7B7%7D%5C%5C%5C%5C%3D%202%5E%7B-2%2B7%7D%5C%5C%5C%5C%3D%202%5E%7B5%7D%5C%5C%5C%5C%3D%202%20%2A%202%20%2A%202%20%2A%202%20%2A%202%5C%5C%5C%5C%3D%2032)
No shes not.
You need to add all the sides if finding perimeter
Answer:
Step-by-step explanation:
a) A relation R is symmetric when it includes the inverse relation, for example if it includes (8,9) then it should also include (9,8), if not, then the relation is not symmetric, you can see that in this case the relation includes (3,4) but not (4,3), therefore it is not symmetric
b) A relation is antisymmetric when it never includes the inverse relation, for example if it includes (8,9) then it can not include (9,8), if it does then it is not antisymmetric. In this case you can see that it first starts with (1,2) but then it also includes (2,1) so then it is not antisymmetric
c) A relation is reflexive if for each number of the domain set it includes the pair that is two times that same number, for example if 8 is in the domain then the relation should include (8,8). if not then it is not reflexive. In this case you can see that the domain S includes 1 but (1,1) is never on the relation or for example (2,2) is also never in the relation.