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KATRIN_1 [288]
2 years ago
11

HELP HELP HELP Quick algebra 1 questions

Mathematics
1 answer:
beks73 [17]2 years ago
5 0

<u>Hello:</u>

<u />

<u>Okay, this problem should be taken in a series of steps</u>:

<u>What is the slope's formula?</u>

  \rm\hookrightarrow  \frac{y_2-y_1}{x_2-x_1}

  • (x₁,y₁) -- first point
  • (x₂,y₂) -- second point

<u>Okay, now let's use this knowledge</u>  

10. (5,-19) and (-5,21)

       Slope = \frac{21--19}{-5-5} =\frac{40}{-10}=-4

11. (12,1) and (12, -1)

      Slope = \frac{-1-1}{12-12} =\frac{-2}{0}

12. (8,7) and (4,7)

     Slope = \frac{7-7}{4-7} =0

<u>Answer:</u>

  • Question 10: -4
  • Question 11: undefined
  • Question 12: 0

Hopefully that helps!

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Answer:

x= 15

Step-by-step explanation:

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sp2606 [1]

Answer:

score 35 is not possible

Step-by-step explanation:

Here, the competitor misses exactly two shots

what we have here is that, if we added from the numbers between 1-10 , excluding exactly two numbers, which of the numbers in the option cannot be obtained by this addition

a) 52

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10

Total is 55

if we removed (2 and 1)

we get 52

This is a possible score

b) 44

Here, we just have to remove 11

if we take off 10 and 1, we can have 44

c) 41

if we removed 4 and 10 ; we get 41

d) 38

if we remove 17, we get 38

so let us remove 10 and 7

e) 35

here, we have to remove 20

Now, no two numbers added between 1 and 10 exactly will give 20

The highest sum to be deducted is 9 + 10 which is 19

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This means that the term 35 is not possible

3 0
3 years ago
Sally works at a store.
Serhud [2]

Answer: <em>Y </em>\geq \frac{1}{2} x+ 20

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Step-by-step explanation:

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3 years ago
Which of the following appear in the diagram below??
insens350 [35]
The ones that appear are A B and C
7 0
3 years ago
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Plz help ill give u brainlist
g100num [7]
Step One
Find the base area  of the large hexagon as though the smaller one was not removed.

Area = 3*Sqrt(3) * a^2 /2 where a is the length of one side of the hexagon
a = 5
Area = 3*sqrt(3) * 25/2 = 75 sqrt(3) / 2 of the large hexagon without the smaller one removed.

Step Two
Find the area of the smaller hexagon. In this case a = 4
Area2 = 3*sqrt(3)*16/2 = 3*sqrt(3)*8 = 24 sqrt(3)

Step Three
Find the area of the thick hexagonal area left by the removal of the small hexagon.

Area of the remaining piece = area of large hexagon - area of the small hexagon

Area of the remaining piece = 75 *sqrt(3)/2 - 24*sqrt(3)

Step Four
Find the volume of the results of the area from step 3
Volume = Area * h
h = 18
Volume = (75 * sqrt(3)/2 - 24*sqrt(3))* 18

I'm going to leave you with the job of changing all of this to a decimal answer. I get about 420 cm^3

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