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KATRIN_1 [288]
2 years ago
11

HELP HELP HELP Quick algebra 1 questions

Mathematics
1 answer:
beks73 [17]2 years ago
5 0

<u>Hello:</u>

<u />

<u>Okay, this problem should be taken in a series of steps</u>:

<u>What is the slope's formula?</u>

  \rm\hookrightarrow  \frac{y_2-y_1}{x_2-x_1}

  • (x₁,y₁) -- first point
  • (x₂,y₂) -- second point

<u>Okay, now let's use this knowledge</u>  

10. (5,-19) and (-5,21)

       Slope = \frac{21--19}{-5-5} =\frac{40}{-10}=-4

11. (12,1) and (12, -1)

      Slope = \frac{-1-1}{12-12} =\frac{-2}{0}

12. (8,7) and (4,7)

     Slope = \frac{7-7}{4-7} =0

<u>Answer:</u>

  • Question 10: -4
  • Question 11: undefined
  • Question 12: 0

Hopefully that helps!

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Find a polynomial function whose graph passes through ​(6,13),(10,-10) and (0,5)
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Answer:

Find a polynomial function whose graph passes through (6,13), (9,-11), (0,5)

1 Answers

Assuming a quadratic, we have that

y = ax^2 + bx + c

Since (0,5) is on the graph, c =5

And we have the remaining system

a(9)^2 + b(9) + 5 = -11

a(6)^2 + b(6) + 5 = 13 simplify

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36a + 6b = 8 multiply through by -9 ⇒ -324a -54b = -72 (2)

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162a = -168

a = -28/27

To find b we have

36 (-28/27) + 6b = 8

-112/3 + 6b = 8

⇒ b = 68/9

The function is

y = - (28/27)x^2 + (68/9)x + 5

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The answer to the question

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In basketball, hang time is the time that both of your feet are off the ground during a jump.
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