Question

a number is chosen ar random from 1 to 25. find the probaility of selecting an even number or multiple of 3

Answer 1

Answer:

16/25 or 64%

Step-by-step explanation:

There are 12 even numbers between 1 and 25: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, and 24

There are 8 multiples of 3 between 1 and 25: 3, 6, 9, 12, 15, 18, 21, and 24

That makes your odds 20/25. But, you can't count numbers twice! So eliminate the repeats and you get:

2, 3, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, and 24

which is 16/25 numbers that satisfy being an even number, a multiple of 3, or both

hope this helped :)