Answer:
Step-by-step explanation:
30. Given: rectangles QRST and RKST
Prove: ΔQSK is isosceles
An isosceles triangle is a triangle which has two sides and two angles to be equal.
Thus,
From rectangle QRST, the diagonals of rectangles are similar.
i.e RT ≅ QS (diagonal property)
Also, RT ≅ SK (opposite sides of rectangle RKST)
Thus,
RT ≅ QS ≅ SK
Therefore,
ΔQSK is an isosceles triangle.
31. Given: Rectangles QRST, RKST and JQST
Prove: JT ≅ KS
From rectangle QRST, the diagonals of rectangles are similar.
i.e RT ≅ QS (diagonal property)
But,
JT // QS and RT // KS
Thus,
JT ≅ QS (opposite sides of rectangle JQST)
also,
RT ≅ KS (opposite sides of rectangle RKST)
So that,
JT ≅ QS ≅ RT ≅ KS
Therefore,
JT ≅ KS
This is a standard relationship/systems of equations question. Here is how you attack it. Firstly, set up equations to represent the relationships. Ed = 4*Kim That shows that Ed has four times as many pins as Kim. Next, we see that the two have 25 together. So: Ed + Kim = 25 Now we have our two equations. In order to solve, we need to get one of the equations down to one variable. We can achieve this via substitution. The first equation tells us that we can substitute 4*Kim for Ed (in the second equation). So, let's do just that: 4*Kim + Kim = 255*Kim = 25Kim = 5 Using the first equation again, we can solve for Ed: Ed = 4*KimEd = 4*(5)<span>Ed = 20</span>
Answer:
15
Step-by-step explanation:
The product of the prime factors of 3375 are
3375 = 3³ × 5³, then
![\sqrt[3]{3375}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3375%7D)
= ![\sqrt[3]{3^3(5^3)}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%5E3%285%5E3%29%7D)
= ![\sqrt[3]{3^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%5E3%7D)
× ![\sqrt[3]{5^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E3%7D)
= 3 × 5
= 15
Answer:
ok so it would take more effort to lift the 1 newton that is 4 m
Step-by-step explanation:
Work is done when a an object with a certain weight is moved at a given distance;
It is the product of force and distance and therefore varies directly to both distance and force.
Work = Force × distance;
For a 4 N box 0.5 m;
Work = 4 × 0.5
= 2 Joules
For a 1 N box 4 m
Work = 1 × 4
= 4 Joules
Therefore, Lifting a 1 N box for 4 m, will take more work
hope this helps
~ukiahsmith1
P.S pls mark brianliest
have a nice day :D
Answer:
Step-by-step explanation:
This graph is the parent function y = (1/4)x shifted down 3 units
So....the correct answer is : f(x)=(1/4)x −3
