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3 years ago

6

What is the value of x in the equation Negative StartFraction 6 over 7 EndFraction = Negative StartFraction x over 84 EndFractio

n?

2 answers:

ycow [4]3 years ago

5 0

Answer:

c =72

Step-by-step explanation:

Vinil7 [7]3 years ago

4 0

Answer:

C: 72

Step-by-step explanation:

I took the test on edge

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WHat is 2x2x2x2x2x2+2=<br> 66<br> 76<br> 86<br> 96<br> 106

Alexeev081 [22]

Answer:

66

Step-by-step explanation:

$2 \times 2 \times 2 \times 2 \times 2 \times 2+2= \\ \\ = 64 + 2 \\ \\ = 66$

5 0

4 years ago

For the right triangles below, find the exact values of the side lengths and .

konstantin123 [22]

Answer:

$c=\frac{2\sqrt{3}}{3}$

h= $3\sqrt{2}$

Step-by-step explanation:

Please see the attached image. It is a good idea it to memorize these triangle properties because you will definitely use them in the future.

c= $\frac{2}{\sqrt{3} } =\frac{2*\sqrt{3} }{\sqrt{3} *\sqrt{3} } =\frac{2\sqrt{3}}{3}$

h= $3\sqrt{2}$

5 0

3 years ago

1221 bottles is packaged in 3 sacks.will there be any bottle leaf over? how do you know?

Levart [38]

Answer:

407

$1221 \div 3 = 407$

there wont be any left overs

7 0

3 years ago

The Royal Fruit Company produces two types of fruit drinks. The first type is 20% pure fruit juice, and the second type is 95% p

enot [183]

Answer:

14 pints of 20% juice

56 pints of 95% juice

Step-by-step explanation:

Let

x be pints of 20% pure fruit juice, thus

70 - x will be pints of 95% pure fruit juice

The equation, thus can be written as:

20%x + 95% (70-x) = 80% (70)

Solving for x:

$(0.2)x + (0.95)(70-x) = (0.8)(70)\\0.2x+66.5-0.95x=56\\0.75x=10.5\\x=14$

And 70 - x would be 70 - 14 = 56

Thus,

14 pints of 20% juice is needed, and

56 pints of 95% juice is needed

5 0

3 years ago

Read 2 more answers

Differentiating Functions of Other Bases In Exercise, find the derivative of the function.

aniked [119]

Answer:

$\dfrac{dy}{dx} = \frac{2x-3}{\ln 16(x^2 - 3x)}$

Step-by-step explanation:

We are given the following in the question:

$y = \ln {16}(x^2 - 3x)$

We have to find the derivative of the given expression.

$y = \ln 16(x^2 - 3x)\\\text{Using the log propert}\\\\\log_a b = \dfrac{\log b}{\log a}\\\\dfrac{d(x^n)}{dx} = nx^{n-1}\\\\\dfrac{d(\log x)}{dx} = \dfrac{1}{x}\\\\\text{\bold{Differentiating we get}}\\\\\displaystyle\frac{dy}{dx} = \frac{d(\ln 16(x^2-3x))}{dx}\\\\= \frac{1}{16(x^2-3x)})\frac{d(x^2-3x)}{dx}\\\\=\frac{1}{\log 16(x^2-3x)}(2x - 3)\\\\= \frac{2x-3}{\ln 16(x^2 - 3x)}$

$\dfrac{dy}{dx} = \frac{2x-3}{\ln 16(x^2 - 3x)}$

7 0

4 years ago