What is the probability that a two-digit number selected at random has a tens digit less than its units digit
1 answer:
The probability that a two-digit number selected at random has a tens digit less than its units digit is 0.2667 (4/15).
There are 90 two-digit numbers (99-9). Of these, six numbers are divisible by 15 (15, 30, 45, 60, 75, 90). This is also divisible by 5. Therefore, the preferred case is 30-6 = 24. Therefore, the required probability is 24/90 = 4/15.
The probability of an event can be calculated by simply dividing the number of favorable results by the total number of possible results using a probabilistic expression. Whenever you are uncertain about the outcome of an event, you can talk about the probability of a particular outcome, that is, its potential.
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Answer:
D. a is equal to
Step-by-step explanation:
Let us assume that segment PQ is 8 units, so that its midpoint M is at 4 units to both P and Q.
Given that X is the midpoint of PM, this implies that X is at 2 units to both P and M.
Then;
PX = aPQ
⇒ = a x 8
= 8a
Therefore, a must be equal to , so that;
PX = 8a
= 8 x
= 2 units
Thus, a is equal to is the correct option.