Question

What is the probability that a two-digit number selected at random has a tens digit less than its units digit

Answer 1

The probability that a two-digit number selected at random has a tens digit less than its units digit is 0.2667 (4/15).

$A=24B=90\\\\P=A/B\\\\P=24/90\\p=4/15$

There are 90 two-digit numbers (99-9). Of these, six numbers are divisible by 15 (15, 30, 45, 60, 75, 90). This is also divisible by 5. Therefore, the preferred case is 30-6 = 24. Therefore, the required probability is 24/90 = 4/15.

The probability of an event can be calculated by simply dividing the number of favorable results by the total number of possible results using a probabilistic expression. Whenever you are uncertain about the outcome of an event, you can talk about the probability of a particular outcome, that is, its potential.

Learn more about probability here: brainly.com/question/24756209

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