Answer:
B. 1/(3xy^3)
Step-by-step explanation:
The minus sign can be dealt with first, then the root taken.
![\left(9x^{2}y^{6}\right)^{-\frac{1}{2}}=\dfrac{1}{\sqrt{9x^{2}y^{6}}}\\\\=\dfrac{1}{\sqrt{9}\sqrt{x^2}\sqrt{y^6}}=\dfrac{1}{3xy^3}](https://tex.z-dn.net/?f=%5Cleft%289x%5E%7B2%7Dy%5E%7B6%7D%5Cright%29%5E%7B-%5Cfrac%7B1%7D%7B2%7D%7D%3D%5Cdfrac%7B1%7D%7B%5Csqrt%7B9x%5E%7B2%7Dy%5E%7B6%7D%7D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B%5Csqrt%7B9%7D%5Csqrt%7Bx%5E2%7D%5Csqrt%7By%5E6%7D%7D%3D%5Cdfrac%7B1%7D%7B3xy%5E3%7D)
Answer:
36 minutes is the answer!
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
![2h^2](https://tex.z-dn.net/?f=2h%5E2)
Step-by-step explanation:
=> ![(10h^4+h^2)-(10h^4-h^2)](https://tex.z-dn.net/?f=%2810h%5E4%2Bh%5E2%29-%2810h%5E4-h%5E2%29)
=> ![10h^4+h^2-10h^4+h^2](https://tex.z-dn.net/?f=10h%5E4%2Bh%5E2-10h%5E4%2Bh%5E2)
=> ![h^2+h^2](https://tex.z-dn.net/?f=h%5E2%2Bh%5E2)
=> ![2h^2](https://tex.z-dn.net/?f=2h%5E2)
Answer:
71
Step-by-step explanation:
[6x4(15/5)]+[2^2+(1x-5)]
BIDMAS (aka PEDMAS etc.)
Brackets
Indices
Division/Multiplication
Addition/Subtraction
[6 x 4(15/5)] + [2^2 + (1x-5)]
[6 x 4(3)] + [2^2 + (-5)]
[6 x 4(3)] + [4 + -5]
[6 x 12] + [4 + -5]
[72] + [4 + -5]
72 + [-1]
72 + - 1
72 - 1
71