3 years ago

If f(x)=x and g(x)=2, what is (f o g)(x)?

Mathematics

1 answer:

IgorC [24]3 years ago

6 0

Answer:

= 2x

Step-by-step explanation:

You might be interested in

What is the number in scientific notation? 0.0765

devlian [24]

Answer:

$7.65 * 10^{-2}$ is scientific notation of 0.0765

Step-by-step explanation:

For scientific notation , follow the following notation:

$a * 10^{b}$ -------->(equation 1)

Let, $a^{'} = 0.0765$

In standard form

$a = 7.65$

As decimal point move 2 places from left to right, therefore

b = -2

Put the value of 'a' and 'b' in (equation 1)

$7.65 * 10^{-2}$ is scientific notation of 0.0765

4 0

3 years ago

Find the area of a triangle with sides a = 5, b = 8, and c = 11

Sergio039 [100]

Well the formula for a triangle is base(b) times height(h) divided by 2.

6 0

3 years ago

Mila wants to buy a scooter for Rs 62,000 . She has only Rs 19,000 with her, so she decides to take a loan from a bank for the r

Aneli [31]

Answer:

Scheme a 45000 is the answer

8 0

2 years ago

Read 2 more answers

If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

6 0

3 years ago

The expression 28 + 63 is equivalent to<br> 1 91<br> 2 5,7<br> 3 6/7<br> 4 13,7

Yuliya22 [10]

Answer:

1) 91

Step-by-step explanation:

28 + 63 = 91

3 0

2 years ago