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Liono4ka [1.6K]
3 years ago
9

On her lunch break, Audrey grabs a meal with her two coworkers. If everyone paid an equal amount of $8.50, then how much was the

total bill?
Mathematics
1 answer:
UNO [17]3 years ago
7 0

Answer:

$25.50

Step-by-step explanation:

3 people including Audrey went on the lunch break. If each spent $8.50, the total bill can be calculated in two ways

<u>Method 1 </u>

$8.50 x 3 = $25.50

<u>Method 2 </u>

$8.50 + $8.50 + $8.50 = $25.50

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А Campus athletics is interested in the proportion of registered students living on campus who play basketball recreationally du
r-ruslan [8.4K]

Answer:

c. We are 95% confident that, among the population of students that play basketball recreationally, the proportion who live on campus is between 0.12 and 0.18.

Step-by-step explanation:

According to the question, it is mentioned that there is 95% confidence interval and it is calculated (0.12,0.18)

So the correct interpretation is that they are 95% confident that the students who play basketballs the proportion should lies between 0.12 and 0.12

So, the option C is correct

The rest of the options are wrong

3 0
3 years ago
Paul borrowed $360 to be repaid in one year. He paid 10% interest and a service
Art [367]

Answer:

Step-by-step explanation:

Hey, do you mean what is the final charge? If so, then look at my next steps

If you mean the final charge then first multiply 10% by 360 , basically 10/100 multiplied by $360 which is equals to $36. Since it is interest, add $36 to $360. The answer will be $396. Then you add on the $19 which would bring the total to $415.

Hehe I am no expert but this is what I did . Tried my best

4 0
4 years ago
HELP ASAP WILL MARK BRAINLY
vodomira [7]

Answer:

\frac{61}{99}

Step-by-step explanation:

let x = 0.616161 (etc.)

make a second equation because you multiply by 100:

100x = 61.616161 (etc.)

subtract from each other

100x = 61.616161

     x =  0.616161

you get

99x = 61

solve for x

\frac{61}{99}

5 0
4 years ago
Last basketball season John made 62% of the free throws he attempted. In the first game this season, John went to the free-throw
Step2247 [10]

Answer:

62 x 10 =620

Step-by-step explanation:

multiply

5 0
3 years ago
What are the coordinates of the endpoints of the midsegment for △JKL that is parallel to KL⎯⎯⎯⎯⎯? Enter your answers in the boxe
algol [13]
The points you are looking for are the midpoints of segments JL and JK.
J(-2, -1), K(4, -5), L(0, -5)

The midpoint of segment JL is

(-2 + 0)/2, (-1 + (-5))/2) = (-2/2, -6/2) = (-1, -3)

The midpoint of segment JK is

(-2 + 4)/2, (-1 + (-5))/2) = (2/2, -6/2) = (1, -3)

Answer: The coordinates are (-1, -3), (1, -3)
6 0
3 years ago
Read 2 more answers
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