Answer:
Step-by-step explanation:
Assuming there is a punitive removal of one point for an incorrect response.
Five undiscernable choices: 20% chance of guessing correctly -- Expectation: 0.20*(1) + 0.80*(-1) = -0.60
Four undiscernable choices: 25% chance of guessing correctly -- Expectation: 0.25*(1) + 0.75*(-1) = -0.50
I'll use 0.33 as an approzimation for 1/3
Three undiscernable choices: 33% chance of guessing correctly -- Expectation: 0.33*(1) + 0.67*(-1) = -0.33 <== The approximation is a little ugly.
Two undiscernable choices: 50% chance of guessing correctly -- Expectation: 0.50*(1) + 0.50*(-1) = 0.00
And thus we see that only if you can remove three is guessing neutral. There is no time when guessing is advantageous.
One Correct Answer: 100% chance of guessing correctly -- Expectation: 1.00*(1) + 0.00*(-1) = 1.00
<em>For</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>image</em><em>,</em><em> </em><em>note</em><em> </em><em>that</em><em> </em><em>slope</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>thing</em><em> </em><em>as</em><em> </em><em>gradient</em><em>.</em>
1) y = 2x + 4
2) Substituting in x = 1 and y = 1,
1 = 4(1) + c
1 = 4 + c
c = -3
So, the equation is y = 4x - 3
Answer: When the data given is spread across the graph at random in no certain order
Step-by-step explanation:
Answer:
I can’t just tell you the answer cause that’s all your looking for let me know what u need help with
Step-by-step explanation:
