Question

Algebra 1 A Adaptive CR (JL22) 1/Tools Of The Trade

Answer 1

The simplified expression of $(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$ is $\frac{4^7x^2}{3^2y^2}$

How to simplify the expression?

The expression is given as:

$(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$

Expressions raise to power 0 is 1.

So, we have:

$(4^3)(\frac{4^4x^4}{3^2x^2y^2})$

Apply the law of indices to expression with common base

$(\frac{4^{4+3}x^{4-2}}{3^2y^2})$

Evaluate the sum and difference

$(\frac{4^7x^2}{3^2y^2})$

Remove the bracket

$\frac{4^7x^2}{3^2y^2}$

Hence, the simplified expression of $(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$ is $\frac{4^7x^2}{3^2y^2}$

Read more about exponents at:

brainly.com/question/847241

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