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Ksivusya [100]
3 years ago
9

Find the probability that when a fair coin is flipped four times at least 2 heads

Mathematics
1 answer:
salantis [7]3 years ago
8 0
Since the problem states "at least" we need to also find probability of 3 H or 4 H or 5 H

Now find the probability of flipping a head 4 times; \frac{1}{2}⁴
= (1/16) 

Now probability of flipping a head 3 times: (4C3)(1/2)⁴ = 4/16

Probability of flipping a head 2 times; (4C2)(1/2)⁴=6/16 

(1/16)+(4/16)+(6/16)=11/16

Probability of flipping a fair coin 4 times with at least 2 heads is 11/16.

Hope I helped :) 
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Not likely because in my class we have more boys then girls 
m=27
f=5
8 0
3 years ago
Which two integers is √56 between?<br> Please help me.
lozanna [386]

Answer:

7 and 8.

Step-by-step explanation:

When we check out what is √49 and √64, we can see that they equal 7 and 8 respectively. Since √56 is between √49 and √64, we can say that √56 is between 7 and 8.

Hoped this helped.

8 0
2 years ago
Ok this should be easy:]
Blizzard [7]

Answer:

this is 8 raise to power 18

7 0
3 years ago
Read 2 more answers
Necesito las respuestas
Stels [109]

Answer:

I need it in English please so I can helps

3 0
1 year ago
Y=143.3(5)^2+1823.3(5)+6820
MA_775_DIABLO [31]

As the question is written, the <em>correct answer</em> is:


19519.


Explanation:


Our question states

y = 143.3(5)² + 1823.3(5) + 6820


To evaluate this, we use the order of operations (PEMDAS). There is nothing to be evaluated in parentheses, so P is taken care of.


The E part, exponents, is 5². This is 25, which gives us:

y = 143.3(25) + 1823.3(5) + 6820


Next we have M and D, multiplication and division (in the order they appear). Our multiplication is:

143.3(25) = 3582.5; and

1823.3(5) = 9116.5.


This gives us:

y = 3582.5 + 9116.5 + 6820


Lastly, we add these:

y = 12699 + 6820

y = 19519

6 0
3 years ago
Read 2 more answers
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