Find the probability that when a fair coin is flipped four times at least 2 heads
1 answer:
Since the problem states "at least" we need to also find probability of 3 H or 4 H or 5 H
Now find the probability of flipping a head 4 times;
⁴
= (1/16)
Now probability of flipping a head 3 times: (4C3)(1/2)⁴ = 4/16
Probability of flipping a head 2 times; (4C2)(1/2)⁴=6/16
(1/16)+(4/16)+(6/16)=11/16
Probability of flipping a fair coin 4 times with at least 2 heads is 11/16.
Hope I helped :)
Now find the probability of flipping a head 4 times;
= (1/16)
Now probability of flipping a head 3 times: (4C3)(1/2)⁴ = 4/16
Probability of flipping a head 2 times; (4C2)(1/2)⁴=6/16
(1/16)+(4/16)+(6/16)=11/16
Probability of flipping a fair coin 4 times with at least 2 heads is 11/16.
Hope I helped :)
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Answer:
Option B. t=5/3w ;1/3
Step-by-step explanation:
We are told that varies Inversely with
thus generally speaking
∝
since they are inverted, <u>otherwise</u> if they were proportionally varied then
∝
. This means that there is a constant value (
) for which
is inversely proportional to
and can be mathematically expressed as:
Eqn. (1)
Now since we are given the values of and
, we can plug them in Eqn. (1) and find our constant of proportionality
as follow:
Now that we have our constant we can find the new value for the second value of
as follow:
Therefore based on the options give, we can see that Option B. is correct since
and for
, then