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2 years ago

Find f^-1(x) and it’s domain.

Mathematics

1 answer:

Mrac [35]2 years ago

7 0

Answer: A

Step-by-step explanation:

Letting $f(y)=x$ ,

$x=\sqrt{y}-5\\\\x+5=\sqrt{y}\\\\y=(x+5)^{2}$

Also, the domain of an inverse is the same as the range of the original function, so the range is $x \geq 0$

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Which information is typically found on a map key?

Elodia [21]

Answer:

The Answer is (A)

Step-by-step explanation:

A sample of each symbol (point, line, or area), and a short description of what the symbol means

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2 years ago

Two coplanar lines that are perpendicular to the same line are parallel.

Semenov [28]

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3 years ago

Read 2 more answers

Which inverse operation should be performed first?: m = 7 = 32.

Mumz [18]

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3 years ago

Can someone help me answer this

KonstantinChe [14]

First find the little square (2x3= 6) then the big one is 5x3= 15 (subtract three from 6) and then add them 15+6=21
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4 0

3 years ago

Help me please. 30 points :)

Nataly [62]

$\frac{(5 \: - \: 8x)}{( \sqrt{5 \: - \: 8x} )} \: = \: \sqrt{5 \: - \: 8x}$
For the result to be Real,
$5 \: - \: 8x \: \geqslant \: 0$
$8x \: \leqslant \: 5$
$x \: \leqslant \: \frac{5}{8}$
$( \frac{(5 - 8x)}{( \sqrt{5 - 8x} )} ) \: \times \: (\frac{ \sqrt{5 - 8x} }{ \sqrt{5 - 8x} } ) \: = \: \frac{ {(5 \: - \: 8x)}^{ \frac{3}{2} } }{(5 \: - \: 8x)}$
Hence,
$\frac{{(5 \: - \: 8x)}^{ \frac{3}{2} } }{(5 \: - \: 8x)}$
is the required form.

3 0

3 years ago