Since length of diagonal ( 
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.
<u>Step-by-step explanation:</u>
Here we have , A circle has diameter of 11 cm A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:
We know the concept that for any square to fit inside the circle without touching the edge of circle , diagonal of square must be less than diameter of circle . Let's find out length of diagonal by using Pythagoras Theorem :
For a square , 
⇒ 
⇒ 
⇒ 
⇒
Since length of diagonal ( ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.
Line (a) is y = -3 and line (b) is y = -2x
The prime factorization is 3.
Steps:
1. Break 54 into 2 parts, I broke them into 2 and 27.
2. Since 2 is prime, leave it as is and break 27 into 2. I got 3 and 9.
3. 3 is prime so leave it alone. Break 9 into 3 and get 3 and 3. Your prime factor is 3.
Now, you need the prime factorization, which, if I remember correctly, is the prime factors that you left and did not break apart. List these in order from least to greatest. Your prime factorization should end up looking like this:
2 x 3 x 3 = 54
Answer:
When x = 1 and z = 4, 
Step-by-step explanation:
The variation described in the problem can be written using a constant of proportionality "b" as:
The other piece of information is that when x = 5 and z = 1, then y gives 25/9. So we use this info to find the constant "b":
Knowing this constant, we can find the value of y when x=1 and z=4 as:
Answer: The extra-size chart
- 5 basketball
- 3 footballs
- 5 running
- 3 jogging
- 4 jumping jacks
- 5 sit up
Step-by-step explanation:
