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Marysya12 [62]
2 years ago
5

2/x+3/y=9/x;4/x+9/y=21/xy(x=0,y=0)​

Mathematics
1 answer:
vova2212 [387]2 years ago
7 0

The solution to the equations 2/x+3/y=9/xy; and 4/x+9/y=21/xy are x = 1, and y = 3.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The complete question is:

Solve for x and y:

2/x+3/y=9/xy; and 4/x+9/y=21/xy   x ≠ 0, y ≠ 0

We have two equations:

2/x+3/y=9/xy;

4/x+9/y=21/xy

Solving substitution method:

\rm \dfrac{4}{\dfrac{9-2y}{3}}+\dfrac{9}{y}=\dfrac{21}{\dfrac{9-2y}{3}y}

y = 3

x = 1

Thus, the solution to the equations 2/x+3/y=9/xy; and 4/x+9/y=21/xy are x = 1, and y = 3.

Learn more about the linear equation here:

brainly.com/question/11897796

#SPJ1

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Answer:

20%

Step-by-step explanation:

all you do in this is divide the smaller nymber by the bigger number:

600/3000

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3 years ago
Use the rule to find the naxt five terms in pattern: 10,18,26,34,......
Alinara [238K]
The rule seems to be to add 8. 10+8=18+8=26+8=34+8=42. I hope this helps!
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3 years ago
Sqaure root of 5 (u-1)(u^5+u^4+u^3+u^2+u+1)
Anna71 [15]
GIVEN:

5(u - 1)( {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u + 1)

remember:

\sqrt{u} = {u}^{ \frac{1}{2} }

And

{u}^{n} \times {u}^{m} = {u}^{n + m}

SOLVE:

start by multiplying the factors:

5( ({u}^{6} + {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u ) - ( {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u + 1))

simplify by combing like terms. Most terms subtract off, leaving:

5( {u}^{6} - 1)

This can be factored, but it is not a perfect square, which is really what we need to take the square root.

5( {u}^{3} - 1)( {u}^{3} + 1)

I'm not exactly sure what form they want the answer in...

so taking the square root:

\sqrt{5( {u}^{6} - 1) } = {(5( {u}^{6} - 1))}^{ \frac{1}{2} }

so my best answer is:

{5}^{ \frac{1}{2} } \times {( {u}^{6} - 1)}^{ \frac{1}{2} }
or the more factored form:

{5}^{ \frac{1}{2} } { ({u}^{3} - 1)}^{ \frac{1}{2} } { ({u}^{3} + 1 )}^{ \frac{1}{2} }

I'm not sure how else to solve it. Taking the square root doesn't work out super well, so I left it in the most simple form I could.

sorry for not coming to a definitive answer!
7 0
3 years ago
Suppose that we try to solve the matrix equation AX = B by using an inverse matrix, but find that even though the matrix A is a
Tanzania [10]

Answer:

  The system will be found to be inconsistent or dependent.

Step-by-step explanation:

The matrix A will have no inverse for two different reasons:

  1. The system is inconsistent
  2. The system is dependent

In the latter case, the Gauss-Jordan method will find a set of parametric equations for a solution. In the former case, there is no solution.

The outcome will depend on the reason why there is no inverse.

7 0
3 years ago
What is the value of 1,608 divided by 10 cubed
valkas [14]

Answer:

16 2/25

Step-by-step explanation:

1608 / 10^2

1608/100

16 8/100

16 4/50

16 2/25

8 0
2 years ago
Read 2 more answers
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