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solmaris [256]
3 years ago
12

PLEASE HELP Which relation is a function?!

Mathematics
1 answer:
tia_tia [17]3 years ago
4 0

The answer is the third one aka C.

There must not be two points on the same y-axis because that doesn't make a function but a relation instead.

C. doesn't have 2 points on same y-axis and therefore the third picture is the relation that's a function.

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The value of x varies directly with y, and when x=1/3,y=5
pickupchik [31]

Answer: y = 36x

Step-by-step explanation: Given that x and y vary directly then the equation relating the is

y = kx ← k is the constant of variation

To find k use the condition x = , y = 12, then

k =  =  = 12 × 3 = 36

y = 36x ← equation of variation

3 0
2 years ago
Julie assembles shelves for a department store and gets paid $3.25 per shelf. She can assemble 5 per hour and works 8 hours per
Jlenok [28]

Pay per shelf = $3.25

No of shelfs per hour = 5

Total hours per day = 8

Total days to find pay of = 7

= 3.25×5×8×7

= 910

Therefore she is paid $910 after 1 week.

Must click thanks and mark brainliest

5 0
3 years ago
Please Help <br> dont answer unless you really know the answer
Misha Larkins [42]
Hello, the answer to your question is B-0.8cm. Hope you have a good day!
8 0
3 years ago
Simplify 5b^-8 (Five B to the negative eighth power)
Olenka [21]

Answer:

5

---------

b^8

Step-by-step explanation:

5 b^ -8

We don't like to have negative power

We put it in the denominator

5

---------

b^8

4 0
3 years ago
Look at the figure XYZ in the coordinate plane. Find the perimeter of the figure rounded to the nearest tenth.
ki77a [65]

the distance form X to Y is clearly -6 to 0 is 6 units, and 0 to 8 is 8 units, so 6 + 8 = 14 units.

now, for XZ and ZY we can simply use as stated, the distance formula to get those and then add them all to get the perimeter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ X(\stackrel{x_1}{-6}~,~\stackrel{y_1}{2})\qquad Z(\stackrel{x_2}{5}~,~\stackrel{y_2}{8})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ XZ=\sqrt{[5-(-6)]^2+[8-2]^2}\implies XZ=\sqrt{(5+6)^2+(8-2)^2} \\\\\\ XZ=\sqrt{121+36}\implies \boxed{XZ=\sqrt{157}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ Z(\stackrel{x_2}{5}~,~\stackrel{y_2}{8})\qquad Y(\stackrel{x_2}{8}~,~\stackrel{y_2}{2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ ZY=\sqrt{(8-5)^2+(2-8)^2}\implies ZY=\sqrt{9+36}\implies \boxed{ZY=\sqrt{45}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{perimeter}{14+\sqrt{157}+\sqrt{45}}\qquad \approx \qquad 33.2

6 0
3 years ago
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