1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
cricket20 [7]
2 years ago
8

if you are examining a triangle with given measurements for one leg and the hypotnuse,how will you determine the measure of the

unknown leg?
Mathematics
1 answer:
Alexus [3.1K]2 years ago
6 0

We will apply the Pythagoras theorem to find the measure of the unknown leg in a triangle when one leg and the hypotenuse are provided dimensions.

<h3>What is the definition of a right-angle triangle?</h3>

It's a form of a triangle with one 90-degree angle that follows Pythagoras' theorem and can be solved using the trigonometric function.

According to Pythagoras, the sum of the squares of two sides equals the square of the longest side.

\rm h^2 = p^2+ b^2

Where,

h is the hypotenuse

p is the perpendicular

b is the base

If any of the two is given the third side will be obtained using the  Pythagoras theorem.

In a triangle with given measurements for one leg and the hypotenuse, we will determine the measure of the unknown leg by the Pythagoras theorem.

Hence we willl apply the pythogorous theorem for finding the unknown side.

To learn more about right-angle triangles, refer to brainly.com/question/3770177.

#SPJ1

You might be interested in
What kinds of regular polygons can be used for regular tessellations? Check all that apply.
Fiesta28 [93]

Answer:

Step-by-step explanation:

The regular polygons that can be used to form a regular tessellation are an equilateral triangle, a square, and a regular hexagon.

Hope it helps

plz mark as brainliest!!!!!!

4 0
3 years ago
Read 2 more answers
An Expression that represents 40% of a number is 40n
kumpel [21]
Is this a true or false question?
5 0
3 years ago
Read 2 more answers
Let a1, a2, a3, ... be a sequence of positive integers in arithmetic progression with common difference
Bezzdna [24]

Since a_1,a_2,a_3,\cdots are in arithmetic progression,

a_2 = a_1 + 2

a_3 = a_2 + 2 = a_1 + 2\cdot2

a_4 = a_3+2 = a_1+3\cdot2

\cdots \implies a_n = a_1 + 2(n-1)

and since b_1,b_2,b_3,\cdots are in geometric progression,

b_2 = 2b_1

b_3=2b_2 = 2^2 b_1

b_4=2b_3=2^3b_1

\cdots\implies b_n=2^{n-1}b_1

Recall that

\displaystyle \sum_{k=1}^n 1 = \underbrace{1+1+1+\cdots+1}_{n\,\rm times} = n

\displaystyle \sum_{k=1}^n k = 1 + 2 + 3 + \cdots + n = \frac{n(n+1)}2

It follows that

a_1 + a_2 + \cdots + a_n = \displaystyle \sum_{k=1}^n (a_1 + 2(k-1)) \\\\ ~~~~~~~~ = a_1 \sum_{k=1}^n 1 + 2 \sum_{k=1}^n (k-1) \\\\ ~~~~~~~~ = a_1 n +  n(n-1)

so the left side is

2(a_1+a_2+\cdots+a_n) = 2c n + 2n(n-1) = 2n^2 + 2(c-1)n

Also recall that

\displaystyle \sum_{k=1}^n ar^{k-1} = \frac{a(1-r^n)}{1-r}

so that the right side is

b_1 + b_2 + \cdots + b_n = \displaystyle \sum_{k=1}^n 2^{k-1}b_1 = c(2^n-1)

Solve for c.

2n^2 + 2(c-1)n = c(2^n-1) \implies c = \dfrac{2n^2 - 2n}{2^n - 2n - 1} = \dfrac{2n(n-1)}{2^n - 2n - 1}

Now, the numerator increases more slowly than the denominator, since

\dfrac{d}{dn}(2n(n-1)) = 4n - 2

\dfrac{d}{dn} (2^n-2n-1) = \ln(2)\cdot2^n - 2

and for n\ge5,

2^n > \dfrac4{\ln(2)} n \implies \ln(2)\cdot2^n - 2 > 4n - 2

This means we only need to check if the claim is true for any n\in\{1,2,3,4\}.

n=1 doesn't work, since that makes c=0.

If n=2, then

c = \dfrac{4}{2^2 - 4 - 1} = \dfrac4{-1} = -4 < 0

If n=3, then

c = \dfrac{12}{2^3 - 6 - 1} = 12

If n=4, then

c = \dfrac{24}{2^4 - 8 - 1} = \dfrac{24}7 \not\in\Bbb N

There is only one value for which the claim is true, c=12.

3 0
2 years ago
If a gallon of milk costs $5.25 now and the price is
adelina 88 [10]

Answer: It will take approximately 21 years.

Step-by-step explanation:

6 percent of 5.25 is 0.315 (5.25 x 0.06 = 0.315)

Then you subtract 5.25 from 12 to calculate the number of years. (12 - 5.25 = 6.75)

Divide 0.315 from 6.75 (6.75 / 0.315 ≈ 21.4)

5 0
3 years ago
The volumes of two bodies are measured to be
valentinak56 [21]

Answer:

Sum of volumes = (16.6 ± 0.03) cm³

Difference of volumes = (3.8 ± 0.03) cm³

Step-by-step explanation:

Solution

V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³.

∆V = ± (∆V₁ + ∆V₂)

= ± (0.02 + 0.01) cm³

= ± 0.03 cm³

V₁ + V₂ = (10.2 + 6.4) cm³ = 16.6 cm³ and

V₁ - V₂ = (10.2 - 6.4) cm³ = 3.8 cm³

Hence, sum of volumes = (16.6 ± 0.03) cm³

and difference of volumes = (3.8 ± 0.03) cm³

<u>-TheUnknownScientist</u>

5 0
3 years ago
Read 2 more answers
Other questions:
  • To show that 4 points are the vertices of a rhombus, which of the following must be shown? A. All sides are of equal length. B.
    11·2 answers
  • Angle A and angle B are supplementary. The measure of angle A is 4 less than 7 times the measure of angle B. Find the measure of
    14·1 answer
  • Assume that the proportion of voters who prefer Candidate A is p = 0.617 . Organization D conducts a poll of n = 5 voters. Let X
    10·1 answer
  • In △DEF, DF = 17 and m∠F=32. Find DF to the nearest tenth.
    8·1 answer
  • Josie took a road trip. She drove for 45 minutes at 70 miles per hour. Then she drove 15 minutes at 20 miles per hour. How far d
    6·1 answer
  • What is the measure of arc QSR?
    11·2 answers
  • A local fish market is selling fish and lobsters by the pound. The fish, f, costs $5.00 a pound, while the lobster, l, costs $8.
    6·1 answer
  • 5/6 plus blank equals to 5/2
    8·1 answer
  • 288 times 66 =?<br> Plz help
    5·2 answers
  • May I please receive help?
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!