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Lubov Fominskaja [6]
3 years ago
13

Mrs Rodriguez will make name tags for each of the 45 choir members and 30 orchestra members the materials for each name tag cost

$0.44 what is the total cost of the materials Mrs Rodriguez will use to make these name tags. N. How to do the work
Mathematics
1 answer:
n200080 [17]3 years ago
8 0
45 x 0.44 = ?
30 x 0.44 = ?

Then add the two answers together.
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1/3 of the fish in the tank are snappers. 2/9 of the fish are catfish and the rest are goldfish. There are 40 goldfish in the ta
Paraphin [41]

<u>Find fraction of snappers and catfish:</u>

1/3 + 2/9 = 3/9 + 2/9 = 5/9


<u>Find fraction of goldfish:</u>

1 - 5/9 = 4/9


4/9 = 40 goldfish

1/9 = 40 ÷ 4 = 10

9/9 = 10 x 9 = 90


Answer: 90 fish in the tank


3 0
3 years ago
Read 2 more answers
Cherries cost $5 for two pounds and $7.50 for 3 pounds. a. What is the cost per pound? b. Is it constant? c. If you were to grap
Debora [2.8K]
It is Constant. The cost per pound is 2.50 dollars. two would be on the x-axis, and 5 dollars would be on the y-axis. likewise, 3 would be on the x-axis, and 7.50 dollars is on the y-axis. 5 pounds would cost : $12.50
4 0
3 years ago
Read 2 more answers
PLEASE HELP
kolbaska11 [484]

Answer:

  • a) P(x) = 32000*1.04^x
  • b) $37435
  • c) During year 7

Step-by-step explanation:

<u>Given</u>

  • Initial pay = $32000
  • Increase rate = 4%

a. <u>Formula</u>

  • P(x) = 32000*1.04^x

b. Year 5 is after 4 years, so we are looking for the value of P(4)

  • P(4) = $32000*1.04^4 = $37435

c. <u>P(x) = 40000, x = ?</u>

  • 40000 = 32000*1.04^x
  • 1.04^x = 40000/32000
  • 1.04^x = 1.25
  • log 1.04^x = log 1.25
  • x = log 1.25 / log 1.04
  • x = 5.69, this is 6 years after

The required number of the years is 6 + 1 = 7

3 0
2 years ago
Its due today pls help ASAP
Maksim231197 [3]

Answer:

39

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
When Rafael emptied his pockets, e found he had a total of $3.50 in quarters and nickels. If he had 8 more quarters that nickels
jasenka [17]
You can use systems of equations for this one.

We are going to use 'q' as the number of quarters Rafael had,
and 'n' as the number of nickels Rafael had.


You can write the first equation like this:
3.50=0.05n+0.25q
This says that however many 5 cent nickels he had, and however many
25 cent quarters he had, all added up to value $3.50.
Our second equation is this:
q=n+8
This says that Rafael had 8 more nickels that he had quarters.

We can now use substitution to solve our system.

We can rewrite our first equation from:
3.50=0.05n+0.25q
to:
3.50=0.05n+0.25(n+8)

From here, simply solve using PEMDAS.

3.50=0.05n+0.25(n+8)     --Distribute 0.25 to the n and the 8
3.50=0.05n+0.25n+2     --Subtract 2 from both sides
1.50=0.05n+0.25n     --Combine like terms
1.50=0.30n     --Divide both sides by 0.30
5=n     --This is how many NICKELS Rafael has.

We now know how many nickels he has, but the question is asking us
how many quarters he has.

Simply substitute our now-known value of n into either of our previous
equations (3.50=0.05n+0.25q or q=n+8) and solve.

We now know that Rafael had 13 quarters.

To check, just substitute our known values for our variables and solve.
If both sides of our equations are equal, then you know that you have
yourself a correct answer.

Happy math-ing :)
5 0
2 years ago
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