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Anna [14]
3 years ago
6

4) Graph f(x) 2(3)*. Compare the graph to the

Mathematics
1 answer:
Naddik [55]3 years ago
6 0

Answer  it is 65

Step-by-step explanation:

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Which polynomial equations have -i as one of their roots?
pochemuha
I = sqrt(-1)
i^2 = -1
(-i)^2 = (-i)(-i) = i^2 = -1
(-i)^3 = (-i)(-i)(-i) = (-i)(i^2) = i

use these facts to find which equation is correct if x = -i

i bet on 2,3 or 4
8 0
3 years ago
In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion
lys-0071 [83]

\displaystyle
(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k

<em>-------------------------------------------------------------</em>


\displaystyle&#10;(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\&#10;n=5\\&#10;k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10

<u>It's 10.</u>

----------------------------------------------------

\displaystyle&#10;(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\&#10;n=5\\&#10;k=4\\\\&#10;\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90

<u>It's 90</u>

6 0
4 years ago
Which is the value of the expression ((10^4)(5^2)/(10^3)(5^3))^3
dimulka [17.4K]

Answer:

8

Step-by-step explanation:

Let's set this up to see if we can simplify it a bit:

(\frac{10^4*5^2}{10^3*5^3})^3

Notice we have 4 tens on top and 3 on bottom, so we can eliminate the bottom 3 altogether and leave just one on top.  And we have 2 fives on the top and 3 on bottom, so we can eliminate the 2 on the top and leave one on the bottom.  Now that looks like this:

(\frac{10}{5})^3

10 divided by 5 is 2, and 2 cubed is 8

8 0
3 years ago
Dillon has 4 blue marbles and 3 times as many red marbles.Max has 8 times as many red marbles as Dillon.How much red marbles do
SCORPION-xisa [38]
Dillion has 4 blue marbles and 12 red marbles

And max has 96 red marbles
5 0
3 years ago
The answer for this problem
ElenaW [278]

Only the 3. option can be used. All other values dont fit


4 0
4 years ago
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