Segment PT || segment QS, Given
segment PT ≅ segment QS,
∠T ≅ ∠S
Angle TPQ = Angle SQR PR is a transversal cutting parallel segments SQ and TP
So....it makes corresponding angles TPQ and SQR equal
ΔPQT ≅ ΔQRS ASA congruency
Since supplementary angles are angles that equal to 180, you first need to subtract 40 from 180 to find out what the equation equals. This is the layout of the equation. 140=4x+20. Next you subtract 20 from each side, 120=4x then you divide by 4 four, x=30.
Answer:
135
Step-by-step explanation:
15x18/2=135
..........
Answer:
A=23512.32
Step-by-step explanation:
The equation for the area of a cylinder is A=2πrh+2πr^2
If we substitute the radius and height, the equation would be A=2π(60)(2.4)+2π(60)^2
π can be shortened to 3.14 so it's A=2(3.14)(60)(2.4)+2(3.14)(60)^2
We're left with 904.32+22608
So the answer is 23512.32
Answer:
Matty is a bit of a weirdo you know what i mean
Step-by-step explanation:
