Answer:
y=2x
Step-by-step explanation:
Answer: approximately normal
Step-by-step explanation:
1/2 Thinking about population shape and sample size
When a population is normally distributed, the sampling distribution of the sample mean x will also be normal regardless of sample size.
Since the distribution of distances is normal, the sampling distribution of the sample mean distance will also be normal.
2/2 Answer
The sampling distribution of the sample mean distance will be approximately normal.
Answer:
Step-by-step explanation:
=7 (1+11+111+1111......n)
=7/9 (9+99+999+9999....n)
=7/9 ((10-1)+(10^2-1)+(10^3-1)+....n)
=7/9 ((10+10^2+10^3...n)-(1+1+1+1.....n))
=7/9 ((10 (10^n-1)/(10-1))-n)
