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3 years ago

HELP PLEASE LOOK AT PICTURE

Mathematics

1 answer:

diamong [38]3 years ago

6 0

As all lines are parallel to each other and HI is perpendicular to AB and LM is perpendicular to AB,
hence,
that angles are equal

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For what value of a does (1/7)^3a+3=343^a-1

NemiM [27]

Answer:

a=0

sbsuqvhqua2hw7avwbs7zbehsbz zhs

5 0

3 years ago

If tñ=2ñ+3, find S10

Allisa [31]

Answer:

$S_{10}=280$

Step-by-step explanation:

Given that,

$t_n=2n+3$ ...(1)

We need to find the value of $S_{10}$ .

Put n = 1 to find the first term.

$t_1=2(1)+3=5$

Put n = 2 to find the second term.

$t_2=2(2)+3=7$

Put n = 3 to find the third term.

$t_3=2(3)+3=9$

Put n = 10 to find the tenth term.

$t_{10}=2(10)+3=23$

It means we need to find the sum of 5,7,9,.....,23.

The formula for the sum of n terms is given by :

$S_=\dfrac{n}{2}(a+a_n)$

We have, n = 10, a = 5 and $a_n=23$

So,

$S=\dfrac{10}{2}(5+23)\\\\S_{10}=10\times 28\\\\=280$

So, the value of $S_{10}$ is equal to 280.

3 0

3 years ago

(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)

laiz [17]

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if $K(t)\neq 0$

Example of a second order nonlinear ODE:

$Y=-3K(Y){2}$

(D) Example of a nonlinear fourth order ODE:

$K^4(x) - \beta f [x, k(x)] = 0$

4 0

4 years ago

Help ASAP! 20 Points!

ANTONII [103]

Volume of cylinder is 3 times of volume of cone having same base diameter and same height.

Solution:

Given that

A cylinder and A cone have the same diameter = 10 inches and same height = 12 inches

Need to find the relationship between volume of cylinder and cone.

Let’s calculate volume of each object separately first.

Calculation of volume of cylinder :

Formula of volume of cylinder is given as:

$V_{c y}=\pi r^{2} h$

Where π=3.14

$\text { radius } r=\frac{\text {diameter}}{2}=\frac{10}{2}=5 \text { inches }$

height h = 12 inches

On substituting given values in formula of cylinder we get

$\begin{array}{l}{V_{c y}=3.14 \times 5^{2} \times 12=942 \text { cubic inches }} \\\\ {\text { Volume of cylinder }=V_{c y}=942 \text { cubic inches }}\end{array}$

Calculation of volume of cone:

Formula of volume of cone is given as:

$V_{c o}=\frac{\pi r^{2} h}{3}$

Here π=3.14

$\begin{array}{l}{\text { radius } r=\frac{\text { diameter }}{2}=\frac{10}{2}=5 \text { inches }} \\\\ {\text { height } \mathrm{h}=12 \text { inches }}\end{array}$