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2 years ago

HELP PLEASE LOOK AT PICTURE

Mathematics

1 answer:

diamong [38]2 years ago

6 0

As all lines are parallel to each other and HI is perpendicular to AB and LM is perpendicular to AB,
hence,
that angles are equal

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The base of a triangular prism has an area of 18 square inches . If the height of the prism is 4.5 inches then what is the volum

Nady [450]

Answer:

The volume for the triangular prism is 40.5 cubic inches.

Step-by-step explanation:

Given:

The base of a triangular prism has an area of 18 square inches .

And the height is 4.5 inches.

Now, to get the triangular prism volume.

The base area = 18 square inches.

Height = 4.5 inches.

Now, to get the volume of prism we put formula:

$Volume=\frac{1}{2} \times base\ area\times height\\\\Volume=\frac{1}{2} \times 18\times 4.5\\\\Volume=40.5\ cubic\ inches.$

Therefore, the volume for the triangular prism is 40.5 cubic inches.

7 0

2 years ago

Please Help ASAP! Simplify roots of negative numbers. Express your answer in simplified form.

Korolek [52]

Answer:

$3i\sqrt2$

Step-by-step explanation:

We can rewrite the square root of negative 18 as $\sqrt{18} \cdot\sqrt{-1}$ . We can evaluate these two quantities separately. The square root of 18 can be factored to get 3 squared times 2. We can take the 3 out to get $3\sqrt2$ . Now, the square root of negative one can be rewritten as $i$ , so this is equal to $3i\sqrt2$

7 0

2 years ago

What is the sum? StartFraction 3 y Over y squared + 7 y + 10 EndFraction + StartFraction 2 Over y + 2 EndFraction

katovenus [111]

Answer:

$\dfrac{5}{y+5}$

Step-by-step explanation:

Here, we have to find the sum of 2 fractions:

1st fraction: $\dfrac{3y}{y^{2}+7y+10}$

2nd fraction: $\dfrac{2}{y+2}$

Considering the denominator of 1st fraction:

$y^{2}+7y+10$

Using factorization method:

$7y$ can be written as $(2y + 5y)$ .

$\Rightarrow y^{2}+2y+5y+10$

Taking 5 common from $5y+10$ and y common from $y^{2}+2y$ : $\Rightarrow y(y+2)+5(y+2)$

Now taking $(y+2)$ common:

$\Rightarrow (y+5)(y+2)$

$\dfrac{3y}{y^{2}+7y+10}$ can be written as $\dfrac{3y}{(y+5)(y+2)}$

Now, calculating the sum:

$\dfrac{2y}{(y+5)(y+2)} + \dfrac{2}{y+2}$

Taking LCM and solving:

$\Rightarrow \dfrac{3y+2(y+5)}{(y+5)(y+2)}\\\Rightarrow \dfrac{5y+10}{(y+5)(y+2)}\\\Rightarrow \dfrac{5(y+2)}{(y+5)(y+2)}\\\Rightarrow \dfrac{5}{(y+5)}$