Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.
Honestly I think that it’s c but check that and get back to me
Answer:
Step-by-step explanation:
Juan has 20 books to sell. He sells the books for $15 each.
The range of the function is the set of all possible values of the dependent variable. The dependent variable here is the amount of money that is made and this amount depends on
the number of books, x sold
The amount of money Juan makes from selling books is represented by a fucntion. f(x)=15x
The maximum amount that can be made from 20 books at a rate of $15 each would be 20×15 = $300
The minimum amount that fan be made is $0 and this is when no book is sold. Let y = f(x). So the range is
0 lesser than or equal to y lesser than or equal to 300
Answer:
Step-by-step explanation:
![As\ range=51,\\x-4=51\\x=51+4\ [Adding\ 4\ on\ both\ the\ sides]\\x=55 \\2. x\ is\ the\ lowest\ observation\ or\ x](https://tex.z-dn.net/?f=As%5C%20range%3D51%2C%5C%5Cx-4%3D51%5C%5Cx%3D51%2B4%5C%20%5BAdding%5C%204%5C%20on%5C%20both%5C%20the%5C%20sides%5D%5C%5Cx%3D55%20%5C%5C2.%20x%5C%20is%5C%20the%5C%20lowest%5C%20observation%5C%20or%5C%20x%3C4.%5C%5CHence%2C%5C%5CHighest%5C%20observation%3D48%5C%5CLowest%5C%20observation%3Dx%5C%5CHence%2C%5C%5CAs%5C%20the%5C%20range%5C%20is%5C%2051%2C%5C%5C48-x%3D51%5C%5C-x%3D51-48%20%5BSubtracting%5C%2048%5C%20from%5C%20both%5C%20the%5C%20sides%5D%5C%5C-x%3D3%5C%5Cx%3D-3)
Answer:
The rule is x₁ = 2 x₂ = x₁ * 2 x₃ = x₂ + 3 x₄ = x₃ * 2 x₅ = x₄ + 3 ...
Step-by-step explanation:
Unable to use a single equation to define this sequence
The rule is x₁ = 2 x₂ = x₁ * 2 x₃ = x₂ + 3 x₄ = x₃ * 2 x₅ = x₄ + 3 ...
Multiply 2 then Plus 3 then multiply 2 then plus 3 ......
2,4,7,14,17,34, 37, 74, 77, 154....
