F(x)=x-p

A survey found that women's heights are normally distributed with mean

zheka24 [161]

Answer:

a. 99.30% of the woman meet the height requirement

b. If all women are eligible except the shortest 1% and the tallest 2%, then height should be between 58.32 and 68.83

Explanation:

<em>According to the survey</em>, women's heights are normally distributed with mean 63.9 and standard deviation 2.4

a)

A branch of the military requires women's heights to be between 58 in and 80 in. We need to find the probabilities that heights fall between 58 in and 80 in in this distribution. We need to find z-scores of the values 58 in and 80 in. Z-score shows how many standard deviations far are the values from the mean. Therefore they subtracted from the mean and divided by the standard deviation:

z-score of 58 in= $z=\frac{58-63.9}{2.4}$ = -2.458

z-score of 80 in= $z=\frac{80-63.9}{2.4}$ = 6.708

In normal distribution 99.3% of the values have higher z-score than -2.458

0% of the values have higher z-score than 6.708. Therefore 99.3% of the woman meet the height requirement.

b)

To find the height requirement so that all women are eligible except the shortest 1% and the tallest 2%, we need to find the boundary z-score of the

shortest 1% and the tallest 2%. Thus, upper bound for z-score has to be 2.054 and lower bound is -2.326

Corresponding heights (H) can be found using the formula

$2.054=\frac{H-63.9}{2.4}$ and

$-2.326=\frac{H-63.9}{2.4}$

Thus lower bound for height is 58.32 and

Upper bound for height is 68.83

8 0

3 years ago

To compare the average amount of time that canadians and americans spend commuting, a researcher collects a sample of canadians

yKpoI14uk [10]

The standard error of the difference of sample means is 0.444

From the complete question, we have the following parameters

<u>Canadians</u>

Sample size = 50
Mean = 4.6
Standard deviation = 2.9

<u>Americans</u>

Sample size = 60
Mean = 5.2
Standard deviation = 1.3

The standard error of a sample is the quotient of the standard deviation and the square root of the sample size.

This is represented as:

$SE = \frac{\sigma}{\sqrt n}$

The standard error of the Canadian sample is:

$SE_1 = \frac{2.9}{\sqrt{50}}$

So, we have:

$SE_1 = 0.41$

The standard error of the American sample is:

$SE_2 = \frac{1.3}{\sqrt{60}}$

So, we have:

$SE_2 = 0.17$

The standard error of the difference of sample means is then calculated as:

$SE= \sqrt{SE_1^2 + SE_2^2}$

This gives

$SE= \sqrt{0.41^2 + 0.17^2}$

$SE= \sqrt{0.197}$

Take square roots

$SE= 0.444$

Hence, the standard error of the difference of sample means is 0.444

Read more about standard errors at:

brainly.com/question/6851971

5 0

2 years ago

Among fatal plane crashes that occurred during the past 65 years, 374 were due to pilot error, 51 were due to other human error,

notka56 [123]

Mechanical problems since they can be solved and have the second most deaths. I would have the plane go through at least 3 examinations before boarding then one passenger exam before takeoff.

7 0

3 years ago

Which of the following is not a characteristic of african music? * a. Used primarily in ceremonial rites. B. It has basically in

KatRina [158]

When it comes to African music, it is not true that <u>c. </u><u>African </u><u>traditional </u><u>music </u><u>is largely </u><u>not functional </u><u>in </u><u>nature</u><u>. </u>

<h3>Characteristics of African music</h3>

It is used primarily in ceremonies.
It has a format that can be described as interlocking structural.
It is influenced by several sources.

African music is therefore many things and this allows it to be very functional in nature such that there are several songs that are made for various processes.

In conclusion, option C is correct.

Find out more about African music at brainly.com/question/21946444.

3 0

2 years ago

Ariana is accelerating her car at a rate of 4. 6 m/s2 for 10 seconds. Her starting velocity was 0 m/s. What was her final veloci

Studentka2010 [4]

Answer:

<h3>the answer is v=46 m/s</h3>

Explanation:

<h3>to find the final velocity we use formula from uniformly accelerated motion , equation 1, that is ; V=U+at</h3>

<h3>our given is U=0m/s</h3><h2> a=4.6m/s^2</h2><h3> t=10s</h3><h3>requaired,V=?</h3>

<h3>solution will be; V = u+at</h3>

<h3>replacing the values of each individual</h3>

<h3>V=0m/s+(4.6m/s^2)(10s)</h3><h3>V=0m/s+46m/s ;second found on the unit of acceleration canceled by the unit of time and finaly the left is m/s</h3><h3>V=46m/s</h3>

7 0

2 years ago