In this exercise we have to use the properties of the logarithm to write it in one way, like this:

From these recalling some properties of the logarithm, we find that:
- When the logarithm is equal to the base, the logarithm will always be equal to 1.
- Logarithm of any base, whose logarithm is equal to 1, will always have the result equal to 0.
- Two logarithms with the same base are equal when the logarithms are also equal.
given the equation as:

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Answer:
Social life is the correct answer.
Explanation:
In Project development, Agile Practice is one of the best methods of product delivery because the team is self-organizing and self-managing
<h3>Trait of Agile</h3>
Apart from the two common trait stated above, the agile team is very dynamic and adapts to changes even during production or at any point in the product development cycle.
Other Traits include but not limited to:
- Self-Organizing & Self-Sufficient
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Since supportive measures are designed to preserve both the complainant’s and the respondent’s access to education, interim removal of the respondent may occur if respondent poses an immediate threat or if his/her behavior is said to be disruptive of the said class and interferes with other activities.
<h3>What are supportive measures?</h3>
Supportive measures are known to be any form of an individualized services that is said to be often done so that they can be able to save, restore or keep the equal access of people to education, protect student and employee safety, as well as others.
Note that it is one that act to hinder any form of sexual harassment and as such, Supportive measures are known to be offered even if a the said complainant is a person who do not wish to start or participate in a grievance process.
Therefore, Since supportive measures are designed to preserve both the complainant’s and the respondent’s access to education, interim removal of the respondent may occur if respondent poses an immediate threat or if his/her behavior is said to be disruptive of the said class and interferes with other activities.
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The sampling distribution of the difference in sample means x⁻₁ - x⁻₂ is; 3.5 - 3.5 = 0
<h3>Difference in sample means</h3>
We are told that;
- A fair six-sided die, with sides numbered 1 through 6, will be rolled a total of 15 times.
- x⁻₁ represents the average of the first ten rolls.
- x⁻₂ represents the average of the remaining five rolls.
Now, the average of the largest and lowest numbers of the six sided die is;
E(x) = (6 + 1)/2 = 3.5
Thus, the average mean of the first ten rows is expressed as;
E(x⁻₁) = (n * E(x))/n
E(x⁻₁) = (10 * 3.5)/10
E(x⁻₁) = 3.5
The average mean of the last five rolls will be;
E(x⁻₂) = (n * E(x))/n
E(x⁻₂) = (5 * 3.5)/5
E(x⁻₂) = 3.5
Thus;
x⁻₁ - x⁻₂ = 3.5 - 3.5 = 0
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