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kvv77 [185]
2 years ago
5

I am totally horrible at geometry! can someone help me please

Mathematics
1 answer:
Zanzabum2 years ago
5 0

Answer: 6

Step-by-step explanation:

    We will set up a proportion to solve. Let x be equal to ?.

\displaystyle \frac{3}{5} =\frac{x}{x+4}

    Now, we will cross-multiply.

3 * (x + 4) = 5 * x

3x + 12 = 5x

12 = 2x

6 = x

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3-(-9)÷-10+6<br><br>what is the answer?show work​
Greeley [361]

Answer:

- 12/4

Step-by-step explanation:

3 - (-9) / (-10) + 6

3 + 9 / (-4)

12 / (-4)

- 12/4

6 0
4 years ago
Mike forgot to replace the cap on a bottle of room freshener. The room freshener began to evaporate at the rate of 15% per day.
aleksandrvk [35]
Given:
bottle of room freshener = 40 grams
evaporates at the rate of 15% per day.

f(x) = 40(.85)^x

x    y
1   34
2   28.9
3   24.57
4   20.88
5   17.75

<span>graph of exponential function going down from left to right in quadrant 1 through the point 0, 40 and approaching the x axis</span>
8 0
4 years ago
Read 2 more answers
What is 3 1/3 +(-2 1/4) + 1 5/6 as a mixed fraction
meriva
The answer is 2 11/12 because you do 3 1/3 + -2 1/4 which gets you 1 1/2. Then you need to add 1 5/6 to the 1 5/6 to get your answer. So when you add up your answer you get 2 11/12. Hope this helps.
5 0
4 years ago
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Find the circumference of the circle 2.5cm Use 3.14 for pi.
Misha Larkins [42]

Answer:

0.4

Step-by-step explanation:

3 0
4 years ago
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A peony plant with red petals was crossed with another plant having streaky petals. A geneticist states that 75% of the offsprin
Strike441 [17]

Answer:

The sample data confirm the geneticist's prediction that 75% of the offspring from this cross will have red flowers.

Step-by-step explanation:

A Chi-square goodness of fit test can be used to test the claim made by the geneticist.

The hypothesis is defined as:

<em>H₀</em>: There is no difference between the observed and expected value,i.e. <em>p</em>₁ < 0.75.

<em>Hₐ</em>: There is a significant difference between the observed and expected value, i.e. <em>p</em>₁ > 0.75.

The test statistic is:

\chi^{2}=\sum \frac{(O-E)^{2}}{E}

Consider the tables attached below.

The value of the test statistic is:

\chi^{2}=\sum \frac{(O-E)^{2}}{E}=25.8133

The critical value is:

\chi^{2}_{\alpha, k-1}=\chi^{2}_{0.01, 1}=6.635

*Use a Chi-square table.

The critical region is:

\chi^{2}\geq 6.635

The test statistic value of 25.8133 lies in the critical region.

The null hypothesis is rejected at 1% level of significance.

<u>Conclusion</u>:

As the null hypothesis is rejected it can be concluded that 75% of the offspring from this cross will have red flowers.

7 0
3 years ago
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