Question

Which point-slope equation represents a line that passes through (3, –2) with a slope of negative startfraction 4 over 5 endfraction? y – 3 = –(x 2) y – 2 = (x – 3) y 2 = –(x – 3) y 3 = (x 2)

Answer 1

y = 4x/5 - 22/5

Given slope of line is 4/5 and point is (3,-2)

Slope, Numerical measure of a line's inclination relative to the horizontal. In differential calculus, the slope of a line tangent to the graph of a function is given by that function’s derivative and represents the instantaneous rate of change of the function with respect to change in the independent variable.

The equation of a straight line in the form:

y − y1 = m(x − x1)

where m is the slope of the line  = 4/5  (According to question)

and (x1, y1) are the coordinates of a given point on the line.

compare slope-intercept form.

substituting values

(y+2) = (4/5) (x-3)

⇒ y = 4x/5 - 22/5

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