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3 years ago

PLEASE HELP!!!'Which equation represents a line that is parallel to the line y=-4x+5?

Mathematics

1 answer:

andre [41]3 years ago

7 0

Answer:

A option is right.

Step-by-step explanation:

The slope intercept form of line is y = mx + c where m is inclination of a line.

for any two lines whose slopes are equal then the lines will be parallel to each other. You can see that m for line given in question = -4 and also Option A has m = -4

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E. (x + 5) + (x + 5) =

ladessa [460]

Answer:

Step-by-step explanation:

Hi there!

Here,

= (x+5) + (x+5)

<em>Open bracket</em>

= x+5+x+5

<em>Add like terms</em>

= 2x + 10

= 2(x+5)

Hope it helps!

5 0

3 years ago

How to regroup when subtracting

lbvjy [14]

Just take away 1 from the digit above and add 10 to regroup.

3 0

3 years ago

I think I know how to solve this, but could someone please check my work for me?

Fiesta28 [93]

Answer is :

cos⁻¹[(-1-4√7)/(√17, √8) = 173.33° ≈ 173°

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4 years ago

Two forces of 401 newtons and 477 newtons act on a point. The resultant force is 828 newtons. Find the

Ray Of Light [21]

Answer:

The answer is " $39.01^{\circ}$ "

Step-by-step explanation:

$\to R= 828\\\\\to F_1= 401\\\\\to F_2=477\\\\\to \bold{R=\sqrt{F_1^2+F_2^2+2F_1F_2 \cos \theta}}$

$828=\sqrt{401^2+477^2+2 \times 401 \times 477 \cos \theta}\\\\828=\sqrt{160801+227529+382554 \cos \theta}\\\\828=\sqrt{388330+382554 \cos \theta}\\\\$

square the above equation:

$(828)^2=(\sqrt{388330+382554 \cos \theta})^2\\\\$

$685584 =388330+382554 \cos \theta\\\\685584 -388330=382554 \cos \theta\\\\297254=382554 \cos \theta\\\\\cos \theta=\frac{297254}{382554}\\\\\cos \theta=0.777025\\\\\theta= \cos^{-1} 0.777025\\\\\theta= 39.01^{\circ}$

3 0

3 years ago

If x varies inversely at the cube root of y and x=1 when y =8 find y when x=3

padilas [110]

Answer:

I don't know what this problem is but by how I see it is; the difference between 1 and 8 is 7, so 3+7=10.

Step-by-step explanation:

To see it better;

x-1, y-8 & x-3, y-10

I hope I helped you!!

6 0

2 years ago