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FrozenT [24]
2 years ago
7

Vincent and Aidan buy the same number of pens. Vincent buys packs of 6 pens, and Aidan buys boxes of 20 pens. What is the least

number of pens each boy can have brought?
Mathematics
1 answer:
Shtirlitz [24]2 years ago
3 0

The least number of pens each boy can have brought is 60

<h3>How to determine the least number of pen?</h3>

We have:

Vincent = 6 packs

Aidan = 20 boxes

Factorize 6 and 20

6 = 1 * 2 * 3

20 = 1 * 2 * 2 * 5

Multiply all factors

LCM = 1 * 2 * 2 * 3 * 5

Evaluate the product

LCM = 60

Hence, the least number of pens each boy can have brought is 60

Read more about LCM at:

brainly.com/question/233244

#SPJ1

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Antonia and Carla have the same percentage of green marbles in their bags of marbles. Antonia has 4 green green marbles and 16 t
natulia [17]
Given that Antonia and Carla have the same percentage of marbles and Antonia has 4 green marbles out of 16 marbles , to calculate the number of marbles that Carla has that aren't green we proceed as follows;
let the total number of Carla's marbles be x;
the percentage of green marbles that Antonia has is:
4/16×100=25%

since they have the same percentage then:
number of green marbles Carla has is 10:
this is 25% of x, hence:
10/x×100=25
1000/x=25
1000=25x
thus
x=1000/25
x=40
Carla has a total of 40 marbles. Thus the number of marbles which are not green will be:
40-10=30 marbles


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