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kipiarov [429]
2 years ago
7

Can anyone help me with this ill mark brainliest:

Mathematics
1 answer:
nirvana33 [79]2 years ago
7 0

Answer:

Choice D:

Step-by-step explanation:

If we check them one by one...

Choice A is all correct, so we leave that there for now

Choice B's 3x12 is equal to 36, so therefore it's wrong

Choice C has the same mistake as Choice B - 3x12 is not equal to 32

Choice D is all correct, so therefore it is the answer


Though Choice A is also correct, the question asked for <u>all</u> of the different ways you can arrange the cars

So, therefore... the answer is A!

<u><em>Hope this helped!</em></u>

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The correct answer is 5 cm
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Geico because its car insurance ?
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What is the length of a diagonal of a cube with a side length of 10 cm? 200 cm 210cm 300 cm 320cm
Scilla [17]

Answer:

The length of the diagonal of the cube = √(3 × 10²) = √300 cm

Step-by-step explanation:

* Lets revise the properties of the cube

- It has six equal faces all of them are squares

- It has 12 vertices

- The diagonal of the cube is the line joining two vertices in opposite

 faces (look to the attached figure)

- To find the length of the diagonal do that:

# Find the diagonal of the base using Pythagoras theorem

∵ The length of the side of the cube is L

∵ The base is a square

∴ The length of the diagonal d = √(L² + L²) = √(2L²)

- Now use the diagonal of the base and a side of a side face to find the

 diagonal of the cube by Pythagoras theorem

∵ d = √(2L²)

∵ The length of the side of the square = L

∴ The length of the diagonal of the cube = √[d² + L²]

∵ d² = [√(2L²)]² = 2L² ⇒ power 2 canceled the square root

∴ The length of the diagonal of the cube = √[2L² + L²] = √(3L²)

* Now lets solve the problem

∵ The length of the side of the square = 10 cm

∴ The length of the diagonal of the cube = √(3 × 10²) = √300 cm

- Note: you can find the length of the diagonal of any cube using

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7 0
3 years ago
Read 2 more answers
Help is appreciated! Thanks!
sukhopar [10]

Answer:

  1. 16√3
  2. -45+15i
  3. √255
  4. 6√2 +3√10

Step-by-step explanation:

1)

-4i\sqrt{-48}=-4i\sqrt{(-1)(4^2)(3)}=(-4i)(4i)\sqrt{3}=16\sqrt{3}

__

2)

(-5-5i)(3-6i)=-5(3-6i)-5i(3-6i)=-15+30i-15i+30i^2=-15-30+15i\\\\=-45+15i

__

3)

\sqrt{3}\sqrt{5}\sqrt{17}=\sqrt{3\cdot 5\cdot 17}=\sqrt{255}

__

4)

\sqrt{3}(\sqrt{24}+\sqrt{30})=\sqrt{3\cdot 24}+\sqrt{3\cdot 30}=\sqrt{6^2\cdot 2}+\sqrt{3^2\cdot 10}\\\\=6\sqrt{2}+3\sqrt{10}

_____

The applicable identities are ...

\sqrt{a^2b}=a\sqrt{b}\\\\i^2=-1

7 0
3 years ago
Read 2 more answers
What 1,112,433 rounded to the nearest ten thousand
ValentinkaMS [17]
1,110,000.
You look at the ten thousands value and look at the number after it. If it is less than 5 then it is that number, just add zeros to the rest of the values after it.
5 0
3 years ago
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