Question

I WILL MARK BRAINLIEST A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test. Each adult bike requires 6 hours to build and 4 hours to test. With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week. If c represents child bikes and a represents adult bikes, can the company build 20 child bikes and 6 adult bikes in a week.

Answer 1

Using a system of equations, it is found that since 20 child bikes and 6 adult bikes would require more testing than the allocated time, it is not possible to build this amount.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

• Variable c: number of child bikes.

• Variable a: number of adult bikes.

Each child bike requires 4 hours to build, as do each adult bike. The company has 100 hours of testing, hence:

4c + 4a = 100.

c + a = 25.

With 20 child bikes and 6 adult bikes in a week, we have that c = 20, a = 26, hence:

c + a = 26

20 child bikes and 6 adult bikes would require more testing than the allocated time, it is not possible to build this amount.

More can be learned about a system of equations at brainly.com/question/24342899

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