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ra1l [238]
2 years ago
5

Loss = 10% VAT=13% SP WITH VAT=25,425 now calculate CP

Mathematics
1 answer:
marta [7]2 years ago
7 0

The cost price of the product will be 25000.

<h3>How to calculate the price?</h3>

From the information given, the cost price is 25000. The loss is 10%. This will be:

= 25000 - (10% × 25000)

= 25000 - 2500

= 22500

The tax is 13%. This will be:

= 22500 + (13% × 22500)

= 22500 + 2925

= 25425

Learn more about price on:

brainly.com/question/1153322

#SPJ1

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4 0
3 years ago
Read 2 more answers
1. Use the quadratic, x? + 18x = 25 to answer the following questions.
makvit [3.9K]

Answer:

FIRST PROBLEM:

Exact Form:

x  =  25 /19

Decimal Form:

x =  1.31578947

Mixed Number Form:

x  =  1  6 /19

SECOND PROBLEM

Exact Form:

x  =  − 9  +  √ 106 ,  − 9  − √ 106

Decimal Form: x  =  1.29563014 ,  − 19.29563014

Step-by-step explanation:

5 0
3 years ago
An isosceles triangle has base angles that each measure 39 °. Which equation can be used to fi nd t, the measure of the third an
Montano1993 [528]

Answer: 102°

Step-by-step explanation:

First and foremost, we should note that an isosceles triangle has two sides that are equal and that the sum of angles in a triangle equals to 180°.

Since we are told that the isosceles triangle has base angles that each measure 39°, the third angle will be:

t + 39° + 39° = 180°

t + 78° = 180°

t = 180° - 78°

t = 102°

The third angle is 102°.

5 0
3 years ago
Find the total surface area of this triangle prim 18cm 14cm 30cm 7cm​
AleksandrR [38]

Answer:

48cm

Step-by-step explanation:

8 0
3 years ago
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
3 years ago
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