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Kamila [148]
3 years ago
14

Miki is making bows. She needs 5 inches for one

Mathematics
1 answer:
matrenka [14]3 years ago
7 0

Answer:

she needs 8 inches of ribbon to make both bows.

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EASY POINTS Find the domain of the graphed function.
Vladimir [108]

Using it's concept, it is found that the domain of the graphed function is given as follows:

D. -4 \leq x \leq 2

<h3>What is the domain of a function?</h3>

It is the set that contains all possible input values for the function. In a graph, it is given by the values of x.

In this graph, x assumes values between -4 and 2, inclusive due to the closed circle, hence the domain is given by:

D. -4 \leq x \leq 2

More can be learned about the domain of a function at brainly.com/question/10891721

#SPJ1

4 0
2 years ago
4 1/4 + (-1 3/4) what is the answer
aliya0001 [1]

Answer:

2.5 or 250.

Step-by-step explanation:

7 0
3 years ago
In a class 28 of students, 5 are female and 19 have an A in the class. There are 2 students who are female and have an A in the
telo118 [61]

Step-by-step explanation:

Of the 28 students, 5 are female.  So the probability is 5/28.

5 0
3 years ago
At restaurants waiters typically receive tips that average 15% of the customer’s bill. At this rate, which of the following is t
kodGreya [7K]

Answer:

B $12.69

Step-by-step explanation:

Divide 84.63 by 100 to get 1% of the bill and then multiply the answer by 15 for 15% and round it:

$\frac{84.63}{100} \times 15 = 12.6945$

The closest answer would be B $12.69.

3 0
3 years ago
Rollie was succesful in losing weight he had a goal weight in mind he went on a diet for three months each month he would lose o
Llana [10]
Let's say that in the beginning he weighted x and at the end he weighted x-y, y being the number of kg he wanted to loose.

first month he lost
y/3

then he lost:  
(y-y/3)/3
this is
(2/3y)/3=2/9y
explanation: ((y-y/3) is what he still needed to loose: y minus what he lost already

and then he lost
 (y-2/9y-1/3y)/3+3 (the +3 is his additional 3 pounts)
 (y-2/9y-1/3y)/3-3=(7/9y-3/9y)/3+3=4/27y+3

it's not just y/3 because each month he lost one third of what the needed to loose at the current time, not in totatl

and  the weight at the end of the 3 months was still x-y+3, 3 pounds over his goal weight!


so:  x -y/3-2/9y-4/27y-3=x-y+3

we can subtract x from both sides:
-y/3-2/9y-4/27y-3=-y+3
add everything up:

-19/27y=-y+6

which means
-19/27y=-y+6

y-6=19/27y

8/27y=6
4/27y=3
y=20.25

so... that's how much he wanted to loose, but he lost 3 less than that, so 23.25

ps. i hope I didn't make a mistake in counting, let me know if i did. In any case you know HOW to solve it now, try to do the calculations yourself to see if they're correct!










5 0
3 years ago
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