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2 years ago

A square has a perimeter of 258.8 feet. What is the length of each side?

Mathematics

1 answer:

Lady_Fox [76]2 years ago

7 0

Answer: 64.7

Step-by-step explanation: 258.8 divided by 4

You might be interested in

Cari knows that a certain species of fish need 240 cubic feet of water in their tank.the tank has a height of 12 feet and a widt

pochemuha

The equation that can be used to find the length of the tank is 240 = l × 12 × 10

<h3>How to find the volume of rectangular prism?</h3>

The volume of a rectangular prism can be found as follows:

volume of rectangular prism = lwh

where

l = length
w = width
h = height

Therefore,

volume of rectangular prism = lwh

volume of rectangular prism = 240 ft³

h = 12 ft

w = 10 ft

Therefore, the let's find the length of the tank.

240 = l × 12 × 10

240 = 120l

divide both sides by 120

l = 240 / 120

l = 2

learn more on volume here:brainly.com/question/21308574

#SPJ1

8 0

1 year ago

Solve the system by substitution. y = -4x 23 - 5y = 44

spin [16.1K]

<h3>Explanation</h3>

Given the system of equations.

$\begin{cases} y = - 4x \\ 23 - 5y = 44 \end{cases}$

Substitute y = -4x in the second equation.

$23 - 5( - 4x) = 44 \\ 23 + 20x = 44 \\ 20x = 44 - 23 \\ 20x = 21 \\ x = \frac{21}{20}$

Substitute the value of x in any given equations. I will substitute the value of x in the first equation.

$y = - 4x \Longrightarrow y = - 4( \frac{21}{20} ) \\ y = \cancel{ - 4}( \frac{21}{ \cancel{20}} ) \Longrightarrow y = - \frac{21}{5} \\ y = - \frac{21}{5}$

Answer Check by substituting both values in two equations.

First Equation

$y = - 4x \Longrightarrow - \frac{21}{5} = - 4( \frac{21}{20} ) \\ - \frac{21}{5} = \cancel{ - 4}( \frac{21}{ \cancel{20}} ) \\ - \frac{21}{5} = - \frac{21}{5} \: \: \: \checkmark$

Second Equation

$23 - 5y = 44 \\ 23 - 5( - \frac{21}{5} ) = 44 \\23 - \cancel{5}( - \frac{21}{ \cancel{5}} ) = 44 \\ 23 + 21 = 44 \\ 44 = 44 \: \: \: \: \checkmark$

Both equations are true for the value of x and value of y.

<h3>Answer</h3>

 $\begin{cases} x = \frac{21}{20} \\ y = - \frac{21}{5} \end{cases}$ 

Coordinate Point form

$( \frac{21}{20} , - \frac{21}{5} )$

5 0

2 years ago

10×(2.5+13.5) write the numerical expressions in words then solve

Alex73 [517]

Ten times two point five plus thirteen point five

10 x (2.5 + 13.5) = 160

Hope this helps

-AaronWiseIsBae

6 0

3 years ago

What is 8+[4+(-9)] ?

fgiga [73]

Answer:

Positive 3

Step-by-step explanation:

you have to add 4 and -9 first and you get -5 then you add that to positive 8 and get 3

7 0

2 years ago

Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in

Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - α)% confidence interval for the population variance is given as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

It is provided that:

n = 20

s = 3.9

Confidence level = 95%

⇒ α = 0.05

Compute the critical values of Chi-square:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907$

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

$\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45$

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0

2 years ago