Ask question

Ask question

All categories

2 years ago

5

the students in Mrs. Aubrey's class brought in 15 cans during week 1 of the food drive. during week 2 the students brought in 4

times as many cans. how many cans did the students bring in during week 2?

1 answer:

masha68 [24]2 years ago

8 0

Answer:

30 cans :)

Step-by-step explanation:

We need to divide to solve so lets do that now :)

15 x 4 = 60

60/2 = 30

Have an amazing day!!

Please rate and mark brainliest!!

You might be interested in

A caterpillar eats 75 leaves in 5 hours. How many leaves will the caterpillar eat in 8 hours if it continues to eat at the same

Dahasolnce [82]

Answer:

120 leaves

Step-by-step explanation:

If the caterpillar eats 75 leaves in 5 hours and continues to eat at the same rate, the number of leaves eaten is simple, 120 leaves.

How I found the answer:

First, I divided 75 by 5 and got 15, then I multiplied 8 to 15 and got 120.

3 0

4 years ago

Read 2 more answers

The standard deviation for actuary salaries has a standard deviation of $36,730 . You collect a simple random sample of n=36 sal

Yanka [14]

Using the z-distribution, it is found that the lower limit of the 95% confidence interval is of $99,002.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

The other parameters are given as follows:

$\overline{x} = 111000, \sigma = 36730, n = 36$

Hence, the lower bound of the interval is:

$\overline{x} - z\frac{\sigma}{\sqrt{n}} = 111000 - 1.96\frac{36730}{\sqrt{36}} = 99002$

The lower limit of the 95% confidence interval is of $99,002.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0

2 years ago

Sally's math grade average went from an 84 to a 98. What was the percent of increase in her grade average?

gogolik [260]

Answer:

98 - 84 = 14(this is the change) now we convert this to a percent

14/1 x 100/100 = 14%

3 0

3 years ago

In a department store he finds a square rug that has an area of 9 m2. How many of those rugs are needed to cover an area of 36 s

Svet_ta [14]

Answer:

4

Step-by-step explanation:

Divide the total area by the area of a rug to find the number of rugs.

The total area is 36 m²

The area of a rug is 9m²

36m² ÷ 9m² = 4

Therefore 4 rugs are needed to cover an area of 36 square metres.

8 0

3 years ago

Write an equation in general form for the line passing through (-12,-1) and perpendicular to the line whose equation is 6x-y-4=0

Rus_ich [418]

The Solution:

Given the equation of a line:

$6x-y-4=0$

We are required to find the equation of a line that is perpendicular to the given line and passes through the point (-12,-1).

Step 1:

Determine the slope of 6x-y-4=0.

$\begin{gathered} \text{ Express y in terms of x.} \\ 6x-4=y \\ y=6x-4 \end{gathered}$

The coefficient x, after making y the subject of the formula, is the slope of the given line. That is:

$\begin{gathered} \text{ The slope of }6x-y-4=0\text{ is 6} \\ \\ Slope=m_1=6 \end{gathered}$

Step 2:

Find the slope of the required line:

Since the two lines are perpendicular, the slope is:

$\begin{gathered} m_2=\frac{-1}{m_1}=\frac{-1}{6} \\ \end{gathered}$

Step 3:

Find the equation of the line that passes through point (-12,-1)

By formula,

$y-y_1=m_2(x-x_1)$

In this case,

$\begin{gathered} x_1=-12 \\ y_1=-1 \end{gathered}$

Substituting these values in the formula, we get the required equation is:

$\begin{gathered} y--1=\frac{-1}{6}(x--12) \\ \\ y+1=-\frac{1}{6}(x+12) \end{gathered}$

Cross multiplying, we get

$\begin{gathered} 6y+6=-x-12 \\ \\ 6y+x+6+12=0 \\ \\ 6y+x+18=0 \end{gathered}$

Therefore, the correct answer is:

$6y+x+18=0$

5 0

1 year ago