Answer:
hay I'm sorry that I can't give you the answer but is it okay that we talk as friends
Answer:
In the SAT; Pedagogical relationships are not traditional but those of a group of people working together towards a common goal. Students and tutor challenge specific problems together and face a style of encounter that opens the way to self-learning.
● Within the SAT group, which is at the same time a group of neighbors who share possibilities and problems, learning to dialogue is both an educational objective and a means of training.
Step-by-step explanation:
The purpose of the SAT is for graduates to be competent to perform in their own communities at different levels of activity. The Booster, for example, works at the level of improvement of productive projects within its own productive units or those of its neighbors. The Pilot, in addition to the previous capacity, can organize different types of activities for the common good (health projects, the environment, work with children, recreation, production in solidarity). These two levels are approved by law with the basic secondary. At the Bachelor level, graduates are trained to participate in more complex organizations and develop long-term initiatives in both productive and organizational aspects.
To achieve greater ease and adaptation to the SAT, <em><u>I consider that the group that is being taught with the non-traditional method and where the students work in groups, can easily adapt to the SAT learning system.</u></em>
X=2h, y=3k
Substitute these values into equations.
y+2x = 4 ------> 3k+2*2h=4 -----> 3k +4h =4
2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1
We have a system of equations now.
3k +4h =4 ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1
2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0
4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0
(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0
Denominator cannot be = 0
4h(2-2h)≠0
Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4 or h=-1
Check which
4h(2-2h)≠0
1) h= 3/4 , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.
h=3/4, then 3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then 3k = 4-4*(-1) =8 , 3k=8, k=8/3
So,
if h=3/4, then k=1/3,
and if h=-1, then k=8/3 .
B can i please have brainliest
